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3 years ago

What is the value of x in the equation 3x - 1/9y = 18, when y = 27?

Mathematics

2 answers:

zubka84 [21]3 years ago

8 0

Answer:

x=7

Step-by-step explanation:

prisoha [69]3 years ago

6 0

Answer:

x = 7

Step-by-step explanation:

3x - (1/9)y = 18

*subsitute y as 27, because they are equal to each other*

3x - (1/9)(27) = 18

*multiply and simplify)

3x - (27/9) = 18

*isolate x*

3x - 3 = 18

3x = 21

x = 7

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For every biked mile you run half a mile (1/2)

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3 years ago

Find the perimeter of the polygon. Round your answer to the nearest tenth.

lubasha [3.4K]

Answer:

Perimeter is 38.8 units and approximately 39 units

Step-by-step explanation:

Given: Graph

To find: perimeter of the polygon

Solution:

Distance between points $(x_1,y_1),(x_2,y_2)$ is given by $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

As per the graph,

point P is (-2,11)

point Q is (-4,6)

point R is (2,0)

point S is (1,7)

point T is (8,7)

$PQ=\sqrt{(-4+2)^2+(6-11)^2}=\sqrt{(-2)^2+(-5)^2}=\sqrt{29}=5.4\,\,units\\QR=\sqrt{(2+4)^2+(0-6)^2}=\sqrt{(6)^2+(-6)^2}=\sqrt{72}=8.5\,\,units\\RS=\sqrt{(1-2)^2+(7-0)^2}=\sqrt{(-1)^2+(7)^2}=\sqrt{50}=7.1\,\,units\\ST=\sqrt{(8-1)^2+(7-7)^2}=\sqrt{(7)^2+(0)^2}=\sqrt{49}=7\,\,units\\PT=\sqrt{(8+2)^2+(7-11)^2}=\sqrt{(10)^2+(-4)^2}=\sqrt{116}=10.8\,\,units$

Perimeter refers to sum of lengths of all the sides.

Perimeter = $5.4+8.5+7.1+7+10.8=38.8$

Or approximately 39 units

3 0

3 years ago

PLS PLS HELP, I DONT WANT TO FAIL!!

Flura [38]

Answer:

2.0 seconds

Step-by-step explanation:

Given quadratic functions:

$\begin{cases}y=-7x^2+26x+3\\y=-6x^2 +23x+5\end{cases}$

To find the time, in seconds, that the balloons collided at the highest point, substitute one equation into the other equation and rearrange to equal zero:

$\begin{aligned}-6x^2+23x+5 & = -7x^2+26x+3\\-6x^2+23x+5+7x^2 & = -7x^2+26x+3+7x^2\\x^2+23x+5 & = 26x+3\\x^2+23x+5-26x & = 26x+3-26x\\x^2-3x+5& = 3\\x^2-3x+5-3& = 3-3\\x^2-3x+2& = 0\end{aligned}$

Factor the quadratic:

$\begin{aligned}x^2-3x+2 & = 0\\x^2-2x-x+2 & = 0\\x(x-2)-1(x-2) & = 0\\(x-1)(x-2) & = 0\\\end{aligned}$

Apply the zero-product property to solve for x:

$\implies (x-1)=0 \implies x=1$

$\implies (x-2)=0 \implies x=2$

Therefore, the balloons collided at 1 second and 2 seconds.

To find at which time the highest point of collision occured, substitute both values of x into one of the functions:

$f(1)=-6(1)^2 +23(1)+5=22$

$f(2)=-6(2)^2 +23(2)+5=27$

Therefore, the time, in seconds, that the balloons collided at the highest point is 2.0 seconds.

Learn more about quadratic systems of equations here:

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