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2 years ago

Plssss helppp meeeeee

Mathematics

1 answer:

defon2 years ago

7 0

The last one
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Work out 6/5 of 200 and show working out

katrin [286]

Answer:

240.

Step-by-step explanation:

200 * 6/5

= 1200/5

= 240

5 0

2 years ago

A bag contains 5 red marbles, 6 blue marbles and 9 yellow marbles.

lilavasa [31]

Answer:

Step-by-step explanation:

The total number of marbles is 20

Question A

P(Red) = 4/20 = 1/5

P(yellow) = 9/20

P(Red then Yellow) = 1/5 * 9/20 = 9 / 100

Question B

P(B) = 6/20

P(B again) = 5/19 because you have 1 less total plus 1 less blue.

P(B and B) = 6/20 * 5/19

P(B and B) = 30/ 380 = 3/38

7 0

3 years ago

Consider the diagram.

LenaWriter [7]

Answer:

2 units is perpendicular bisector of line segment

7 0

2 years ago

Figure a is a scale image of figure b. what is the value of x? please answer asap!

emmainna [20.7K]

<em>Greetings from Brasil...</em>

According to the statement, one figure is scaled in relation to another, so we can apply similarity to polygons.....

BIG/small = BIG/small

small/BIG = small/BIG

12.5/10 = X/16

10/12.5 = 16/X

12.5/10 = X/16

10X = 12.5 · 16

X = 200/10

8 0

3 years ago

Pleasantburg has a population growth model of P(t)=at2+bt+P0 where P0 is the initial population. Suppose that the future populat

yulyashka [42]

Answer:

The population will reach 34,200 in February of 2146.

Step-by-step explanation:

Population in t years after 2012 is given by:

$P(t) = 0.8t^{2} + 6t + 19000$

In what month and year will the population reach 34,200?

We have to find t for which P(t) = 34200. So

$P(t) = 0.8t^{2} + 6t + 19000$

$0.8t^{2} + 6t + 19000 = 34200$

$0.8t^{2} + 6t - 15200 = 0$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$0.8t^{2} + 6t - 15200 = 0$

So $a = 0.8, b = 6, c = -15200$

Then

$\bigtriangleup = 6^{2} - 4*0.8*(-15100) = 48356$

$t_{1} = \frac{-6 + \sqrt{48356}}{2*0.8} = 134.14$

$t_{2} = \frac{-6 - \sqrt{48356}}{2*0.8} = -141.64$

We only take the positive value.

134 years after 2012.

.14 of an year is 0.14*365 = 51.1. The 51st day of a year happens in February.

So the population will reach 34,200 in February of 2146.

6 0

2 years ago