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Nimfa-mama [501]
3 years ago
13

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP :O Simple Algebra! I'll give BRAINLIST!!!!!!!! Pls look at the image below. Please do al

l. Tell me which is equivalent. TY. Quick pls
Mathematics
1 answer:
gayaneshka [121]3 years ago
3 0

Answer:

Step-by-step explanation:

There is no picture. Can I have brainly still?

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What is the domain and range of f(x)= |x+6|
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as the function is polynomial domain exist for all real number ie (-infinity to + infinity) but range exist (0 to +infinity ) due to modulus negetive range do not exist

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Julia bought three pumpkins at $.60 a pound. Her first pumpkin weighed 14 pounds, her second weighed 8 pounds, and her third wei
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$18.60

Step-by-step explanation:

First pumpkin

(14)(0.60)

8.4

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7 0
3 years ago
Help! 1. Baby Yoda wants some soup, so he wanders around trying to find some. He starts at the bottom of the grid, and ends clos
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Answer:

huuh yoda

Step-by-step explanation:

7 0
3 years ago
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What is the period of the function below?
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Answer:

4

Step-by-step explanation:

looking at highest peaks

10 - 6 = 4

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3 0
3 years ago
2. Lab groups of three are to be randomly formed (without replacement) from a class that contains five engineers and four non-en
Anna11 [10]

Answer:

The number of different lab groups possible is 84.

Step-by-step explanation:

<u>Given</u>:

A class consists of 5 engineers and 4 non-engineers.

A lab groups of 3 are to be formed of these 9 students.

The problem can be solved using combinations.

Combinations is the number of ways to select <em>k</em> items from a group of <em>n</em> items without replacement. The order of the arrangement does not matter in combinations.

The combination of <em>k</em> items from <em>n</em> items is: {n\choose k}=\frac{n!}{k!(n-k)!}

Compute the number of different lab groups possible as follows:

The number of ways of selecting 3 students from 9 is = {n\choose k}={9\choose 3}

                                                                                         =\frac{9!}{3!(9 - 3)!}\\=\frac{9!}{3!\times 6!}\\=\frac{362880}{6\times720}\\ =84

Thus, the number of different lab groups possible is 84.

8 0
3 years ago
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