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Alla [95]
3 years ago
15

7! What does this mean?

Mathematics
1 answer:
7nadin3 [17]3 years ago
5 0

Answer:

5040

Step-by-step explanation:

7!

= 1 × 2 × 3 × 4 × 5 × 6 × 7

= 5040

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How do I solve this STATS question?
k0ka [10]
We have the following data:

Margin of Error = E = 2.7 % = 0.027
Sample size = n = 900
Proportion of adults in favor = p = 60% = 0.6

We need to find the confidence level. For this first we need to find the z value.

The margin of error for a population proportion is given as:

E=z* \sqrt{ \frac{p(1-p)}{n} }

Using the values, we get:

0.027=z* \sqrt{ \frac{0.6*0.4}{900} } \\  \\ 
0.027=z*0.016 \\  \\ 
z= \frac{0.027}{0.01633}  \\  \\ 
z=1.65

As, seen from the z table, z=1.65 corresponds to the confidence level 90%. So, the answer to this question is option B
7 0
3 years ago
Solve the inequality. Write the solution in set-builder notation.
Salsk061 [2.6K]
-4x - 17 ≥ -41
<u>       +17   +17</u>
        <u>-4x</u> ≥ <u>-24</u>
         -4       -4
           x ≥ 6
8 0
2 years ago
What is the inverse to 2^x-1
nydimaria [60]

Replace x with y and solve for y~

y=2*

x=2^y

log x = y log 2

y=log x / log 2

Hope this helps and leave a brainliest to help me reach expert ;)

4 0
3 years ago
What set of order pairs is a function?
Elza [17]
A function is a set of ordered pairs in which no two different ordered pairs have the same x -coordinate.

Btw you need to add an image so we can see which the order pairs
7 0
3 years ago
An arithmetic sequence has a1 = 22 and a8 = 43. Find a15.
brilliants [131]

The 15th term of the arithmetic sequence a_{15} = 64

Option B is correct

The nth term of an arithmetic sequence is given as:

a_{n} = a + (n - 1)d

The first value, a = 22

a_8 = a+(8 - 1)d\\a_8 = a + 7d

Since a_8 = 43

43 = 22 + 7d\\7d = 43 - 22\\7d = 21\\d = \frac{21}{7}\\d = 3

The common difference, d = 3

a_{15}= a + (15-1)d\\a_{15} = a + 14d\\a_{15} = 22 + 14(3)\\a_{15} = 22 + 42\\a_{15} = 64

The 15th term of the arithmetic sequence = 64

Learn more here: brainly.com/question/24072079

4 0
1 year ago
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