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3 years ago

The price of an item has been reduced by $8.39 . The new sale price is $51.23. What was the original price?

Mathematics

1 answer:

Karolina [17]3 years ago

6 0

Answer:59.62

Step-by-step explanation:

0riginal price=selling price+discount

=51.23+8.39

=59.62

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Anyone down to help? 12pts for PRE-ALGEBRA question Use the information in the table for 2–4.

Anni [7]

Answer:

See attached image

Step-by-step explanation:

If the number of blueberries is the x value, and number of calories is the y value, then we can create the ordered pairs (5,4) (10,8) (15,12) based on the data in the table.

Plotting these on the graph is simple - just go to the x value then the y value and plot where these lines meet.

The slope of a line is always the rise over run.

Every time our x increases by 5, our y increases by 4. The rise is 4, and run is 5, so the slope is $\frac{4}{5}$

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8 0

2 years ago

In 3 years, Dianna will be 4 times as old as she was 33 years ago. How old is Dianna now?

Sergeu [11.5K]

Given that In 3 years, Dianna will be 4 times as old as she was 33 years ago, her present age is 45.

<h3>How old is Dianna now?</h3>

Given that, in 3 years, Dianna will be 4 times as old as she was 33 years ago.

Let x represent the age of Dianna presently.

Dianna's age in 3 years time will be: x + 3

Dianna's age 33 years ago is: x - 33

Since in 3 years, she will be 4 times as old as she was 33 years ago.

x + 3 = 4( x - 33 )

We solve for x

x + 3 = 4x - 132

3 + 132 = 4x - x

135 = 3x

x = 135/3

x = 45

Given that In 3 years, Dianna will be 4 times as old as she was 33 years ago, her present age is 45.

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4 0

2 years ago

Find integra of xlnxdx

Mademuasel [1]

Answer:

$\dfrac{1}{2}x^2\ln x - \dfrac{1}{4}x^2+\text{C}$

Step-by-step explanation:

Fundamental Theorem of Calculus

$\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))$

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

$\boxed{\begin{minipage}{4 cm}\underline{Integrating $x^n$}\\\\$\displaystyle \int x^n\:\text{d}x=\dfrac{x^{n+1}}{n+1}+\text{C}$\end{minipage}}$

Increase the power by 1, then divide by the new power.

Given indefinite integral:

$\displaystyle \int x \ln x \:\: \text{d}x$

To integrate the given integral, use Integration by Parts:

$\boxed{\begin{minipage}{5 cm}\underline{Integration by parts} \\\\$\displaystyle \int u \dfrac{\text{d}v}{\text{d}x}\:\text{d}x=uv-\int v\: \dfrac{\text{d}u}{\text{d}x}\:\text{d}x$ \\ \end{minipage}}$

$\text{Let }u=\ln x \implies \dfrac{\text{d}u}{\text{d}x}=\dfrac{1}{x}$

$\text{Let }\dfrac{\text{d}v}{\text{d}x}=x \implies v=\dfrac{1}{2}x^2$

Therefore:

$\begin{aligned}\displaystyle \int u \dfrac{dv}{dx}\:dx & =uv-\int v\: \dfrac{du}{dx}\:dx\\\\\implies \displaystyle \int x \ln x\:\:\text{d}x & = \ln x \cdot \dfrac{1}{2}x^2-\int \dfrac{1}{2}x^2 \cdot \dfrac{1}{x}\:\:dx\\\\& = \dfrac{1}{2}x^2\ln x -\int \dfrac{1}{2}x\:\:dx\\\\& = \dfrac{1}{2}x^2\ln x - \dfrac{1}{4}x^2+\text{C}\end{aligned}$

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5 0

2 years ago

A2 - 2ab a2 - 4b2

gavmur [86]

(a + 2b) • (a2 - 2ab - 4b2)

6 0

3 years ago

Suppose that 70% of college women have been on a diet within the past 12 months. A sample survey interviews an SRS of 267 colleg

Fofino [41]

Answer:

The probability that 75% or more of the women in the sample have been on a diet is 0.037.

Step-by-step explanation:

Let X = number of college women on a diet.

The probability of a woman being on diet is, P (X) = p = 0.70.

The sample of women selected is, n = 267.

The random variable thus follows a Binomial distribution with parameters n = 267 and p = 0.70.

As the sample size is large (n > 30), according to the Central limit theorem the sampling distribution of sample proportions ( $\hat p$ ) follows a Normal distribution.

The mean of this distribution is:

$\mu_{\hat p} = p = 0.70$

The standard deviation of this distribution is: $\sigma_{\hat p}=\sqrt{\frac{p(1-p}{n}} =\sqrt{\frac{0.70(1-0.70}{267}}=0.028$

Compute the probability that 75% or more of the women in the sample have been on a diet as follows:

$P(\hat p \geq 0.75)=P(\frac{\hat p-\mu_{\hat p}}{\sigma_{\hat p}} \geq \frac{0.75-0.70}{0.028}) =P(Z\geq0.179)=1-P(Z$

**Use the z-table for the probability.

$P(\hat p \geq 0.75)=1-P(Z$

Thus, the probability that 75% or more of the women in the sample have been on a diet is 0.037.

7 0

2 years ago