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Free_Kalibri [48]
3 years ago
7

1.ayah bersepeda motor ke rumah nenek yang jaraknya 9 km dalam waktu 15 menit.berapa km / jam kecepatan sepeda motor?

Mathematics
1 answer:
Helen [10]3 years ago
5 0
Halkalar ne zaman istersen gel ben
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pedro earned gross income of 35200 last year. if he took the standard deduction of 5450 and one exemption of 3500, what was his
Elenna [48]

Answer:

33250

Step-by-step explanation:

Pedro had earned a gross income of 35200 last year.

So, the gross income of Pedro for the current year will also be 35200.

But, this year he has taken the standard deduction of 5450.

Hence, his current year's income will be reduced to (35200-5450)= 29750.

Again, in the current year, he got an exemption of 3500.

Therefore, the net taxable income of Pedro for the current year will become (29750+3500) =33250. (Answer)

4 0
3 years ago
What number should be added to 18 to get a sum of −97?
NARA [144]

x  + 18 =  - 97 \\ x =  - 115
Answer: -115 should be added to 18 to get a sum of -97.

Hope this helps. - M
6 0
4 years ago
PLZ HELP if u know the answer for sure​
krok68 [10]
The answer is b (-2 5/6)
6 0
3 years ago
Need help on this question
Aloiza [94]
I hope this helps you

4 0
3 years ago
What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.
Paul [167]

Answer:

1.60 ft^{2}

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = \pir^{2}

So that,

for the inner part of the pipe,

r = \frac{diameter}{2}

 = \frac{5}{2}

 = 2.5 feet

Area of the inner part of the pipe = \pir^{2}

                                 = 3.14 x (2.5)^{2}

                                 = 19.625

Are of the inner part of the pipe is 19.63 ft^{2}.

Total diameter of the pipe = 5 + 0.2

                                           = 5.2 feet

r = \frac{5.2}{2}

 = 2.6 feet

Area of the pipe = \pir^{2}

                            = 3.14 x (2.6)^{2}

                            = 21.2264

Area of the pipe is 21.23 ft^{2}.

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

                                           = 21.2264 - 19.625

                                           = 1.6014

The cross sectional area of the cement pipe is 1.60 ft^{2}.

6 0
3 years ago
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