3 years ago

If $10,000 is invested in an account at the rate of 6.25% compounded monthly, then the amount after 15 years is approximately

1 answer:

5 0

The formula is
A=p (1+r/k)^kt
A future value?
P present value 10000
R interest rate 0.0625
K compounded monthly 12
T time 15 years
A=10,000×(1+0.0625÷12)^(12×15)
A=25,473.84

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prohojiy [21]

Answer:

$2.25$

Step-by-step explanation:

$(6x^{-2})^2(0.5x)^4\\\\=(6^2(x^{-2})^{2})(0.5^4x^4)\ \ \ \ \ \ \ \ \ \ \ \ \ as\ (ab)^m=a^mb^m\\\\=36\times 0.5^4((x^{-2})^2x^4)\ \ \ \ \ \ \ \ \ \ as\ multiplication\ is\ associative\ a(bc)=(ab)c\\\\=36\times 0.0625(x^{-4}x^4)\ \ \ \ \ \ \ \ \ \ \ as\ (x^m)^n=x^{mn}\\\\=(36\times 0.0625)(x^{-4+4})\ \ \ \ \ \ \ \ \ \ \ as\ x^mx^n=x^{m+n}\\\\=2.25x^0\\\\=2.25\ \ \ \ \ \ \ \ \ \ \ \ as\ x^0=1\\\\(6x^{-2})^2(0.5x)^4=2.25$