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natali 33 [55]
3 years ago
9

What is the radius of the circle?

Mathematics
2 answers:
Flauer [41]3 years ago
7 0

Answer:

\frac{ae}{be}  =  \frac{ce}{de}  =  \frac{bc - be}{ad - ae}  \\  \\  =  >  \frac{8}{3}  =  \frac{15 - 3}{ad - 8}   \\ \\   <  =  >  \frac{8}{3}  =  \frac{12}{ad - 8}   \\  \\  =  > ad - 8 =  \frac{12 \times 3}{8}  = 4.5 \\  \\  <  =  > ad = 4.5 + 8 = 12.5 \\  \\  =  > r = 12.5 \div 2 = 6.25

Stolb23 [73]3 years ago
3 0

Answer:

8×ED=3×15

ED=45/8

the radius is the half of the diameter

so its 45/16

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To answer this question, we need to recall that: "the diagonals of a rectangle bisect each other"

Thus, if we assign the point of intersection of the two diagonals in the rectangle as point O, we can say that the triangle OQR is an "isosceles triangle". Note that this is because the lengths OR and OQ are equal since we know that: "the diagonals of a rectangle bisect each other". See the below diagram for clarity.

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Now, considering the isosceles triangle OQR, we have that:

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\begin{gathered} m\angle2+m\angle2+50^o=180^o \\ \Rightarrow2m\angle2+50^o=180^o \\ \Rightarrow2m\angle2=180^o-50^o \\ \Rightarrow2m\angle2=130^o \\ \Rightarrow m\angle2=\frac{130^o}{2}=65^o \end{gathered}

Therefore, the correct answer is: option D

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