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3 years ago

The hypotenuse of a right triangle is 13 cm. one of the legs is 7 cm longer than the other leg. find the area of the triangle.

1 answer:

8 0

Let one side be=x,the longer side =x+7use pythagoras theoremH^2=b^2+h^2169=x^2+(x+7)^2169=2x^2+14x+490=2x^2+14x-1200=(2x-10)(x+12) x=5 or -12,since it is length x=5 the longer side=5+7=12confirmation169=144+25

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Step-by-step explanation:

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3 years ago

Select the correct answer from each drop-down menu.

Ahat [919]

Answer:

Cos θ = -4/5

Tan θ = -3/4

Step-by-step explanation:

The question is as following:

Select the correct answer from each drop-down menu.

Angle θ lies in the second quadrant, and sin θ =3/5.

cos θ = -4/5, -3/5, 3/5, 4/5

tan θ = -4/3, -3/4, 3/4, 4/3

==================================================

Since, the angle lies in second quadrant (negative x axis and positive y axis) we can deduce that cos θ is negative and tan θ is also negative.

If sin θ =3/5

$cos \ \theta =\sqrt{1-sin^2 \theta} = \sqrt{1-(\frac{3}{5} )^2} =\sqrt{1-\frac{9}{25} }=\sqrt{\frac{16}{25} } =\frac{4}{5}$

∴ Cos θ = -4/5 ⇒ because θ lies in the second quadrant.

And

Tan θ = (sin θ)/(cos θ) = (3/5) / (-4/5) = -3/4.

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Answer:

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Step-by-step explanation:

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