Answer:
a) The number of correct answers
b) Discrete
c) Ratio
Step-by-step explanation:
We are given the following in the question:
Experiment:
Evaluate the effectiveness of different study strategies. All students were then given a test on the passage material and the researchers recorded the number of correct answers.
a) The dependent Variable
The number of correct answers given is the dependent variable because it depends on the number of times the passage is read.
b) Nature of dependent variable.
- It is a discrete variable.
- Since, the number of questions will always be expressed in whole numbers and cannot be expressed as decimals.
- They are always counted and not measured.
c) Scale of measurement
- Ratio is used to measure the dependent variable because true zero for the number of correct questions answered exist.
- If the measure is zero that means truly no questions were answered correctly.
Answer:
Get green green orange green green red green orange
Step-by-step explanation:
, this is payback for answering scrambled words and get the free points, idlot.
Hey there! I'm happy to help!
First, let's find the radius. The radius is half of the diameter.
8.4/2=4.2
Here's how to find the area of a circle.
Square the radius.
4.2²=17.64
And multiply by pi (3.14 in our case)
17.64(3.14)=55.3896
We round to the nearest tenth, giving us an area of 55.4 ft²
Have a wonderful day! :D
Answer:
I NEED THE SAME ANSWER
Step-by-step explanation:
Answer:
The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 20 - 1 = 19
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 1.7291
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample. For this question, we have 
. So
The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.
