a Wheel 15 inches in diameter is spun around 4 full turns. What distance,to the nearest inch, did a mark on the edge of the whee
l travel in those four turns ? explain how you figured out your answer
2 answers:
C=π*d so the distance the mark travels in 1 revolution is 15*π. for 4 revolutions we get 60π and this is approx 189 inches
If the wheel has a diameter of 15 inches, its radius is half that, or 7.5 inches then.
a full turn, or a full cycle around the wheel, namely around the circle is 360° or 2π radians.
now, in one turn or cycle, it covered an angle of 2π, in 2 cycles it covered 2(2π), in 3 it did 3(2π) and in 4 of course 4(2π).
so, what is the arc's length, whose radius is 7.5 and its central angle is 8π?
well.... you already know that s = rθ, therefore then, s = (7.5) (8π).
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A.) x + 8 < 14
-8 -8
x < 6
b.) x - 12 >/= 5.7
+12 +12
x >/= 17.7
Answer:
15
Step-by-step explanation:
x/3 + 3 = 8
x/3 + 9/3 = 8
x + 9 = 24
x = 15
Answer:
Step-by-step explanation:
y 1 = StartFraction log x Over log 0.5 EndFraction, y 2 = StartFraction log 2 Over log 3 EndFraction + x
So you are using Volume...
V=1/3(pi)r^2h
as you go thu this equation
15 x 15 =225
12 x12= 144
225-144= 81
81/9=9
which your piece would be 1/3 pi r^2h answer is 1356.48
and you round it to the nearest tenth. So
( 1356.5) is ur answer...... So (B)
6 1/10 because 3 3/5 equals 3 6/10 and 2 1/2 equals 2 5/10. 3 6/10 plus 2 5/10=6 1/10