Use compound interest formula F=P(1+i)^n twice, one for each deposit and sum the two results.
For the P=$40,000 deposit,
i=10%/2=5% (semi-annual)
number of periods (6 months), n = 6*2 = 12
Future value (at end of year 6),
F = P(1+i)^n = 40,000(1+0.05)^12 = $71834.253
For the P=20000, deposited at the START of the fourth year, which is the same as the end of the third year.
i=5% (semi-annual
n=2*(6-3), n = 6
Future value (at end of year 6)
F=P(1+i)^n = 20000(1+0.05)^6 = 26801.913
Total amount after 6 years
= 71834.253 + 26801.913
=98636.17 (to the nearest cent.)
Answer:
D
Step-by-step explanation:
Answer:
21.46 or 21.5
Step-by-step explanation:
To find the answer to this problem you must divide 877 by 4132, which gets you 0.2146. Then you multiply this answer by 100 to find the percentage; which in this case is 21.46, or 21.5 if you are rounding up. I hope my answer helped you!
Answer:
1.32% of students have the chance to attend the charter school.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
This year the mean on the entrance exam was an 82 with a standard deviation of 4.5.
This means that 
a.What is the percentage of students who have the chance to attend the charter school?
Students who achieve a score of 92 or greater are admitted, which means that the proportion is 1 subtracted by the pvalue of Z when X = 92. So



has a pvalue of 0.9868
1 - 0.9868 = 0.0132
0.0132*100% = 1.32%
1.32% of students have the chance to attend the charter school.