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jenyasd209 [6]
3 years ago
8

The bond between the two atoms acts very much like a spring. a. True b. False

Chemistry
1 answer:
Tatiana [17]3 years ago
5 0

Answer:

a. True

Explanation:

The bonds between atoms are called chemical bonds. These bonds act as though they were a spring holding these atoms together.

When the atoms in a given bond are compressed by decreasing their distance of separation from their equilibrium position, a force provided by the bond tries to prevent these atoms from getting too close than usual. If on the other hand the atoms are stretched by increasing their distance of separation from their equilibrium position, a force provided by the bond tries to pull these atoms together again. This behaviour of the bond is what makes it to be considered as being similar to a spring.

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HELP ASAP PLS <br> Reactions, products and leftovers
Alenkasestr [34]

Answer:

See the answer below

Explanation:

From the original equation in the image, the mole ratio of C:CO2:CO is 1:1:2. This means that for every 1 mole of C and CO2, 2 moles of CO would be produced.

Now, looking at the simulation below the equation of the reaction, 3 moles of C and 8 moles of CO2 were supplied as input. Applying this to the original equation of reaction, C seems to be a limiting reagent for the reaction because the ratio of C to CO2 should 1:1.

Hence, taking all the 3 moles of C available means that only 3 moles out of the available 8 for CO2 would be needed. 3 moles c and 3 moles CO2 means that 6 moles CO would be produced (remember that the ratio remains 1:1:3 for C, CO2, and CO). This means that 5 moles CO2 would be leftover.

<em>In other words, all the 3 moles C would be consumed, 3 out of 8 moles CO2 would be consumed, and 6 moles CO would be produced while 5 moles CO2 would be leftover. </em>

3 0
3 years ago
What is the full electric configuration for cadmium?
jekas [21]

Answer: Kr 4d10 5s2

Explanation:

6 0
4 years ago
COMPARE: Identify three ways that a biologist’s research is similar to an astronomer’s.
dalvyx [7]
  1. Biologist and astronomer both use tools that magnify  so they are able to view minute objects. Astronomers use telescopes while biologists use microscopes.
  2. They both require data science due to the enormous data they are collecting that needs to be analyzed. Astronomers are collecting data on millions of stars and galaxies. Biologists require data science to analyze the enormous genomic data from populations.
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8 0
4 years ago
The rotten smell of a decaying animal carcass is partially due to a nitrogen-containing compound called putrescine. Elemental an
balu736 [363]

The empirical formula is C_2H_6N.

<u>Explanation:</u>

Putrescine has the elements like Carbon, Nitrogen and Hydrogen present in them. So in order to determine the empirical formula, we first have to find the number of moles present in the putrescine. As the percentage of C, H and N present in the chemical is given as 54.50%, 13.73% and 31.77%, we assume that 100 g of Putrescine is taken as sample.

Then the mass of C, H and N present in Putrescine will be 54.50 g, 13.73 g and 31.77 g.  We know that the molar mass of C is 12 g/mol, H is 1 g/mol and N is 14 g/mol.  So divide the mass with the molar mass of the respective elements to determine the number of moles of these elements present in the sample.

<u></u>No.\ of\ moles\ of\ C=\frac{\text { Mass of } C}{\text { Molar mass of } C}=\frac{54.50 \mathrm{g}}{12 \mathrm{g} / \mathrm{mol}}=4.54\ moles<u></u>

Similarly, the number of moles of H and N present is determined.

\text { No. of moles of } H=\frac{\text { Mass of } H}{\text { Molar mass of } H}=\frac{13.73 \mathrm{g}}{1 \mathrm{g} / \mathrm{mol}}=13.73 \text { moles }

No.\ of\ moles\ of\ N=\frac{\text { Mass of } N}{\text { Molar mass of } N}=\frac{31.77 \mathrm{g}}{14 \mathrm{g} / \mathrm{mol}}=2.27\ moles

Then the empirical formula can be determined by dividing the number of moles of all elements with the least number of moles that is 2.27.

    \begin{aligned}&\text { No. of atoms of } C=\frac{4.54}{2.27}=2\\&\text { No. of atoms of } H=\frac{13.73}{2.27}=6\\&\text { No. of atoms of } N=\frac{2.27}{2.27}=1\end{aligned}

So, the empirical formula is C_2H_6N.

3 0
3 years ago
The major use of carbon dioxide​
lidiya [134]

Answer:

Carbon dioxide is used as a refrigerant, in fire extinguishers, for inflating life rafts and life jackets, blasting coal, foaming rubber and plastics, promoting the growth of plants in greenhouses, immobilizing animals before slaughter, and in carbonated beverages.

3 0
3 years ago
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