Explanation:
The hydrological cycle is the continuous cycling of water between land, open water surfaces and the sea. This cycle begins with evaporation, sunlight evaporates water from the surface of earth, next condensation happens, the water absorbed is now used to form clouds, after these clouds are filled to the maximum, precipitation happens, this can be in the form of rainfall and snow, this cycle finalizes when the precipitation of water runs off the land and back into water sources.
Sources of water pollution:
- <em>During precipitation: </em>Smog can be gathered in the atmosphere, during precipitation this pollution can turn into acid rain.
- <em>During runoff:</em> After acid rain hits the ground this polluted water can run into water sources (lakes, rivers, reservoirs).To some extent rivers are a self-renewing resource, if a small quantity of pollution discharges in it the river can return to a clean, unpolluted condition, unfortunately, if the pollution is too big the renewing won't be possible, another problem is even though rivers get cleaned the pollution moves to the seas. Lakes are even more vulnerable to pollution, the flushing effect in these water bodies is less evident than in rivers.
I hope you find this information useful and interesting! Good luck!
Diagram of the nuclear composition, electron configuration, chemical data, and valence orbitals of an atom of neodymium-144 (atomic number: 60), an isotope of this element. The nucleus consists of 60 protons (red) and 84 neutrons (orange). 60 electrons (white) successively occupy available electron shells (rings).
To find the answer you need to use the formula that will help you to find the density. Density = mass/volume
d = 43.2g/96.5mL = 0.45g/mL
The theoretical proportion is given by the balanced chemical equation:
2 mol NBr / 3 mol Na OH
Then x mol NaOH / 40 mol NBr3 = 3mol NaOH/2 mol NBr3
Solve for x, x = 40 * 3/2 = 60 mol NaOH.
Given that there are 48 mol NaOH (less than 60) this is the limitant reactant and the other is the excess reactant.
Answer: NBr3..
