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attashe74 [19]
3 years ago
14

When finding the 9th term in a geometric sequence with a common ratio of 2 and a first

Mathematics
1 answer:
Zarrin [17]3 years ago
5 0

Answer:

8

Step-by-step explanation:

Nth term of a geometric sequence is given as:

t_n = a r^{(n-1)} ...(1)

Plugging n = 9, a = 3 and r = 2 in the above equation, we find:

t_9 = (3) (2)^{9-1}

t_9 = (3) (2)^{8}... (2)

Comparing equations (1) & (2), we obtan:

(n - 1) = 8

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