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Alenkinab [10]
3 years ago
14

Write an equation in slope-intercept form for the line with slope 1/5 and y-intercept 5.

Mathematics
1 answer:
AVprozaik [17]3 years ago
8 0

Answer:

y=1/5x+5

Step-by-step explanation:

Slope-intercept form is written y=mx+b.

y- needs to be by itself in this form.

m- the slope.

x- always to the right side of the slope, or m.

b- y-intercept.

Now that we know this, all we have to do is plug in the numbers we have. So when we plug this in, the equation looks like this:

y=1/5x+5

Hope this helps you and have a great day :3

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What is the unit rate of 4 ticket for 35$
Paraphin [41]

Answer:35/5 = 8.75$ per ticket

Step-by-step explanation:

7 0
2 years ago
An instructor who taught two sections of engineering statistics last term, the first with 25 students and the second with 35, de
Amiraneli [1.4K]

Answer:

a) P=0.1721

b) P=0.3528

c) P=0.3981

Step-by-step explanation:

This sampling can be modeled by a binominal distribution where p is the probability of a project to belong to the first section and q the probability of belonging to the second section.

a) In this case we have a sample size of n=15.

The value of p is p=25/(25+35)=0.4167 and q=1-0.4167=0.5833.

The probability of having exactly 10 projects for the second section is equal to having exactly 5 projects of the first section.

This probability can be calculated as:

P=\frac{n!}{(n-k)!k!}p^kq^{n-k}= \frac{15!}{(10)!5!}\cdot 0.4167^5\cdot0.5833^{10}=0.1721

b) To have at least 10 projects from the 2nd section, means we have at most 5 projects for the first section. In this case, we have to calculate the probability for k=0 (every project belongs to the 2nd section), k=1, k=2, k=3, k=4 and k=5.

We apply the same formula but as a sum:

P(k\leq5)=\sum_{k=0}^{5}\frac{n!}{(n-k)!k!}p^kq^{n-k}

Then we have:

P(k=0)=0.0003\\P(k=1)=0.0033\\P(k=2)=0.0165\\P(k=3)=0.0511\\P(k=4)=0.1095\\P(k=5)=0.1721\\\\P(k\leq5)=0.0003+0.0033+0.0165+0.0511+0.1095+0.1721=0.3528

c) In this case, we have the sum of the probability that k is equal or less than 5, and the probability tha k is 10 or more (10 or more projects belonging to the 1st section).

The first (k less or equal to 5) is already calculated.

We have to calculate for k equal to 10 or more.

P(k\geq10)=\sum_{k=10}^{15}\frac{n!}{(n-k)!k!}p^kq^{n-k}

Then we have

P(k=10)=0.0320\\P(k=11)=0.0104\\P(k=12)=0.0025\\P(k=13)=0.0004\\P(k=14)=0.0000\\P(k=15)=0.0000\\\\P(k\geq10)=0.032+0.0104+0.0025+0.0004+0+0=0.0453

The sum of the probabilities is

P(k\leq5)+P(k\geq10)=0.3528+0.0453=0.3981

8 0
3 years ago
From the set {70, 20, 15}, use substitution to determine which value of x makes the equation true.
Vladimir79 [104]
X=15

Just divide 5x by 5 and 75 by 5
6 0
3 years ago
Can anyone tell me what point I plot these two at pls
zhuklara [117]

Answer:

x^{2} +y^{2}=25

x^{2} +y^{2}=5

<em>Radius: 5</em>

<em>Radius: </em>\sqrt{5}

Step-by-step explanation:

(see images below)

Hope this helped!

~<u>rere</u>

4 0
2 years ago
A percentage is another way to write a _________________.
konstantin123 [22]

Answer:

Ratio, Decimal or Fraction

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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