2) A student performs this reaction in the laboratory, and collects the hydrogen gas over water. The student collects 215.8 mL o
1 answer:
Answer: 0.0086 moles of hydrogen are produced.
Explanation:
According to ideal gas equation:
total pressure = 755.2 mm Hg
pressure of water at = 19.8 mm Hg
P = pressure of hydrogen = (755.2-19.8) mm Hg = 735.4 mm Hg = 0.97 atm
(760 mm Hg = 1atm)
V = Volume of gas = 215.8 ml = 0.2158 L
n = number of moles
R = gas constant =
T =temperature =
Thus 0.0086 moles of hydrogen are produced.
You might be interested in
Here we have to get the spin of the other electron present in a orbital which already have an electron which has clockwise spin.
The electron will have anti-clockwise notation.
We know from the Pauli exclusion principle, no two electrons in an atom can have all the four quantum numbers i.e. principal quantum number (n), azimuthal quantum number (l), magnetic quantum number (m) and spin quantum number (s) same. The importance of the principle also restrict the possible number of electrons may be present in a particular orbital.
Let assume for an 1s orbital the possible values of four quantum numbers are n = 1, l = 0, m = 0 and s = .
The exclusion principle at once tells us that there may be only two unique sets of these quantum numbers:
1, 0, 0, + and 1, 0, 0, -
.
Thus if one electron in an orbital has clockwise spin the other electron will must be have anti-clockwise spin.
Answer:- B. 4.65 g.
Solution:- The given balanced equation is:
It asks to calculate the mass of silver sulfide formed by when 0.0150 liters of 2.50 M of silver nitrate are used.
Moles of silver nitrate are calculated on multiplying it's liters by its molarity and then on multiplying by mol ratio, the moles of silver sulfide are calculated. These moles are multiplied by the molar mass to convert to the grams.
Molar mass of = 2(107.87)+32.06 = 247.8 g per mol
The dimensional set up for the complete problem is:
=
So, the correct choice is B. 4.65 g.