Electronegativity decreases as you go down a colum in the periodic table.
Answer is: pH of aniline is 9.13.<span>
Chemical reaction: C</span>₆H₅NH₂(aq)+
H₂O(l) ⇌ C₆H₅NH₃⁺(aq) + OH⁻(aq).
pKb(C₆H₅NH₂) = 9.40.
Kb(C₆H₅NH₂) = 10∧(-9.4) = 4·10⁻¹⁰.
c₀(C₆H₅NH₂) = 0.45 M.
c(C₆H₅NH₃⁺) = c(OH⁻) = x.
c(C₆H₅NH₂) = 0.45 M - x.
Kb = c(C₆H₅NH₃⁺) · c(OH⁻) / c(C₆H₅NH₂).
4·10⁻¹⁰ = x² / (0.45 M - x).
Solve quadratic equation: x = c(OH⁻) = 0.0000134 M.
pOH = -log(0.0000134 M.) = 4.87.
pH = 14 - 4.87 = 9.13.
You have to balance out those forces and apply the same amount of equal and opposite force to it. I hope I helped ^^
The correct question is
Give the coordination number, the charge of the central metal ion, and select the correct name in each coordination compound:
Na3[CoCl6]
[Ni(CO)4]
[Ni(NH3)3(H2O)2] (NO3)2
Answer:
See explanation for details
Explanation:
Na3[CoCl6]
Name: Sodium hexacholorocobalt III
Charge on the complex: -3
Central metal ion name : cobalt III
coordination number: 6
[Ni(CO)4]
Name: tetracarbonyl nickel (0)
Charge on the complex: 0
Central metal ion name : nickel (0)
coordination number: 4
[Ni(NH3)3(H2O)2] (NO3)2
Name: Diaquatriaminenickel II nitrate
Charge on the complex: +2
Central metal ion name : nickel (+2)
coordination number: 5
I’ll get back to u on this