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Effectus [21]
3 years ago
13

What is the area of the rectangle at right? Show your work (+2 points) 12 14 14 12

Mathematics
2 answers:
Simora [160]3 years ago
8 0
Answer: 168

Explanation: to find the area of a rectangle all you need to do is length times width and you get the answer so in this case we would do 12x14 and get 168 hope this helped
ziro4ka [17]3 years ago
6 0

Answer:

168

Step-by-step explanation:

Area = Length * Width

Area = 14 * 12

Area = 168

Detailed multiplication:

14

* 12

-------

28

+ 140

---------

168

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Solve using Y=Mx+b <br><br> M=-5 and (-3,-2)
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Given:

M=-5 and (-3,-2).

To find:

The equation in the form y=mx+b.

Solution:

The slope intercept form of a line is

y=mx+b          ...(i)

where, m is slope and b is y-intercept.

We have m=-5. Putting m=-5 in (i), we get

y=-5x+b          ...(ii)

We have a point (-3,-2). Putting x=-3 and y=-2 in (ii), we get

-2=-5(-3)+b

-2=15+b

-2-15=b

-17=b

So, the value of b is -17.

Putting b=-17 in (ii), we get

y=-5x+(-17)

y=-5x-17

Therefore, the required equation is y=-5x-17.

8 0
3 years ago
How many sets of 5 students can be selected out of 30 students?
asambeis [7]

There are 142506 ways in which 5 students can be selected out of 30 students.

<h3>How can a certain number of individuals be selected using a combination?</h3>

The selection of 5 students out of 30 students can be achieved with the use of combination since the order of selection is not required to be put into consideration.

By using the formula:

\mathbf{^nC_r = \dfrac{n!}{r!(n-r)!}}

where;

  • n = total number of individual in the set = 30
  • r = number of chosing individuals to be selected = 5

\mathbf{^nC_r = \dfrac{30!}{5!(30-5)!}}

\mathbf{^nC_r = \dfrac{30!}{5!(25)!}}

\mathbf{^nC_r = 142506}

Learn more about combination here:

brainly.com/question/11732255

#SPJ11

4 0
2 years ago
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Answer:

d. he did not make an error

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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