Question

What is the solution to the following system of equations?

Answer 1

Answer:

1.) x=2y-4

2.) x=2y-4 :)

Answer 2

Answer:

$3x - 6y = - 12 ..........i)\\ x - 2y = - 8............ii) \\ x = 2y - 8 \\ Substituting \: the \: value \: of \: x \:in \: equation \: i) \: we \: get \\ 3(2y - 8) - 6y = - 12 \\ 6y - 24 - 6y = - 12 \\ Here \: we \: can \: see \:that\: the \: value \: of \: y \: cannot \: be \: found \\ Equation \: is \: in \: form \: a \frac{}{1} x + b \frac{}{1} y + c \frac{}{1}= 0\:and \\ a \frac{}{2} x + b \frac{}{2} y + c \frac{}{2} = 0 \\ where, \: \: \frac{a \frac{}{1} }{a \frac{}{2} } = \frac{b \frac{}{1} }{b \frac{}{2} } \\ Therefore \: lines \: are \: parallel \: to \: each \: other \\ Lines \: have \: no \: solution.$