Heather has a bag with 16 red blocks, 11 blue blocks, 9 purple blocks, 15 green blocks, 8 yellow blocks, and 20 orange blocks. I
1 answer:
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Answer:
87.73 inches
Step-by-step explanation:
We are given that the dimensions of the rectangular doorway are,
Length = 6 ft 8 inches = 80 inches and Width = 3 feet = 36 inches.
Using Pythagoras Theorem, we will find the diagonal of the rectangular doorway.
i.e.
i.e.
i.e.
i.e.
i.e. Hypotenuse = ±87.73 inches
Since, the length cannot be negative.
So, the length of the diagonal is 87.73 inches.
As, the largest side of a rectangle is represented by the diagonal.
So, the largest dimension that will fit through the doorway without bending is 87.73 inches.
Answer:
Option (B) is true i.e segment B'D' will run through (2,2) and will be longer than the segment BD.
Step-by-step explanation:
As the assumption quadrilateral ABCD is shown in figure a.
First located the center of the dilation which is located at (2,2) as shown in figure b.
The next thing we want to do is to determine the distance of the center of dilation to each of the points of quadrilateral ABCD as shown in figure b.
Let’s just start with the distance from the center to the point A, but notice we don’t have to move up and down in y direction. So, what we have to do is to increase this by the factor 2. Because this horizontal distance is 1 i.e. the distance from dilation center (2,2) to point A, we just have to multiply by 2 which would be a distance of 2 and this point right here will be the new location of point A’ (0,2).
And the distance from the center to the point C is the horizontal distance of 2 i.e. the distance from dilation center (2,2) to point C, we just have to multiply by 2 which would be a distance of 4 and this point right here will be the new location of point C’ (6,2).
And the distance from the center to the point B is the upward vertical distance of 1 i.e. the distance from dilation center (2,2) to point B, we just have to multiply by 2 which would be a vertical distance of 2 and this point right here will be the location of point B’ (2,4).
And similarly the distance from the center to the point D is the downward vertical distance of 1 i.e. the distance from dilation center (2,2) to point D, we just have to multiply by 2 which would be a vertical distance of 2 and this point right here will be the location of point D’ (2,0).
So, Quadrilateral A'B'C'D' is dilated by a scale factor of 2 centered around (2, 2).
Just notice in figure b that the segment B'D' will run through (2,2) and will be longer than the segment BD.
<u>So,option (B) is true</u> <u>i.e segment</u><u> </u><u>B'D' will run through (2,2) and will be longer than the segment BD.</u>
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