True or false. When a girl walks the action of pushing and the equal amd opposite reaction is being projected forward

You decide to travel by car for your holiday visits this year. You leave early in the morning to avoid congestion on the roads.

Bond [772]

Answer:

$d_t=266.918\ miles$ is the total distance of the trip travelled.

$s_{avg}=54.7895\ mph$ is the average speed of the journey

Explanation:

Given:

duration of first interval, $t_1=3.22\ hr$

speed during the first interval, $v_1=65.9\ mph$

duration of stoppage, $t_0=42.1\ min=0.7017\ hr$

duration of second interval, $t_2=0.95\ hr$

speed during second interval, $v_2=57.6\ mph$

Now the total distance travelled:

$\rm distance=speed\times time$

$d_t=v_2.t_2+v_1.t_1$

$d_t=57.6\times 0.95+65.9\times 3.22$

$d_t=266.918\ miles$

The average speed:

$\rm speed_{avg}=\frac{total\ distance}{total\ time\ taken}$

$s_{avg}=\frac{d_t}{(t_0+t_1+t_2)}$

$s_{avg}=\frac{266.918}{(0.7017+3.22+0.95)}$

$s_{avg}=54.7895\ mph$

4 0

4 years ago

The diameter of a copper wire is thought to be approximately 0.3mm. Which instrument should be used to obtain a more accurate me

erica [24]

Answer:

C

Explanation:

The correct answer should be the micrometer.

The micrometer is an instrument that is capable of measuring the component of an object to very high precision. It is used to obtain accurate measurements in engineering.

In the case of the copper wire, the diameter of 0.3 mm was an approximation and a more accurate measure of the diameter would be obtained by using the micrometer.

The correct option is C.

4 0

3 years ago

If an electron moves in a circle of radius 21 cm perpendicular to a B field of 0.4 T, what are the speed of the electron and the

kodGreya [7K]

Answer:

a)

$v = 4.048 *10^6$ m/s

b)

Angular frequency = $1.92 * 10^7$

Explanation:

As we know

$v = \frac{qBr}{m}$

q is the charge on the electron = $3.2 * 10^{-19}$ C

B is the magnetic field in Tesla = $0.4$ T

r is the radius of the circle = $0.21$ m

mass of the electrons = $6.64 * 10^{-27}$ Kg

a)

Substituting the given values in above equation, we get -

$v = \frac{3.2 * 10^{-19}*0.4*0.21}{6.64 * 10^{-27}} \\v = 4.048 *10^6$ m/s

b)

Angular frequency =

$\frac{4.048 * 10^6 }{0.21} \\1.92 * 10^7$

8 0

3 years ago

Two long parallel wires that are 0.30 m apart carry currents of 5.0 A and 8.0 A in the opposite direction. Find the magnitude of

olya-2409 [2.1K]

To solve this problem we will apply the concepts related to electromagnetic force. This force is defined as the product between the free space permeability constant, the product of the two currents found, at the rate of the distance that separates them. In this way mathematically it can be given as,

$F = \frac{\mu_0 I_1I_2 }{2\pi d}$