Answer:
the petrified log looks like the original tree.
Explanation:
A tree to be petrified first needs to be buried. An element laying on the surface can not be petrified because it is exposed to many different factors (such as<em> organisms, microorganisms, climatic conditions</em>, etc.), that affect the petrification process. So, in the case of a fallen tree, first, it needs to be covered by many sedimentary layers. Once it is underground, it also needs the presence of underground water and minerals. Water replaces the original organic material with minerals (silica, calcite, and pyrite). This replacement process results in the conversion of the woody material into a fossil of the original material. Very often, the tree details are so preserved that the fossil looks exactly like the original trunk.
Depending on the preservation degree, a fossil can be useful for different studies about the past.
1. Contraction
2. Actin
3. Tendons
4. Epidermis
5. Dermis
6. Acne
7. A nerve signal from the brain arrives at the intersection of the nerve and muscle cells and releases acetylcholine from the neuron. This triggers chemical changes in the muscle cell involving ions, including Ca2+. Calcium triggers the thick filaments, made of myosin, to attach to the thin filaments, made of actin, in the muscle cell, and the myosin pulls the actin toward the center of the muscle cell. ATP causes the release of the actin fibers, allowing the muscle to relax and the process to begin again.
For Penn Foster.
Two examples of tissue found in plants are xylem and phloem
Plotting a graph of the mass or volume of the product created against time allows you to determine the reaction's pace. This is depicted for two reactions on the graph. The rate of reaction is inversely proportional to the gradient of the line; that is, the steeper the line, the higher the rate of reaction
<h3>What is Rate of reaction ?</h3>
The result is a straight line with a positive gradient on a graph of reaction rate against concentration (a graph showing proportionality).
- The half-life is constant in a concentration-time graph of first order. As a result, the period of time it takes for the concentration to decrease to 50% of its initial value is constant.
- It would be considered first order if you obtained a straight line with a negative slope. If you graph the inverse of the concentration for second order
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