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m_a_m_a [10]
2 years ago
8

The force newton(N),between two particles is inversely propotional to the square of the distance ,d m,between them.When particle

s are 2metere apart,the force between them is 10 newton.Find the force between the particles when the are 5 metere apart
Mathematics
1 answer:
bonufazy [111]2 years ago
6 0

Answer: 1.6\ N

Step-by-step explanation:

Given

The force between the two particles is inversely proportional to the distance between them

\Rightarrow F\propto \dfrac{1}{d^2}

When the distance is 2 m, the force is 10 N. For 5 m distance, it is

\Rightarrow \dfrac{10}{F_o}=\dfrac{5^2}{2^2}\\\\\Rightarrow F_o=10\times \dfrac{2^2}{5^2}\\\\\Rightarrow F_o=1.6\ N

Thus, the force between them is 1.6\ N

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Multiply 2.19 × 43.7 = ____
makkiz [27]
Hello your correct answer would be 95.703 
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7 0
3 years ago
Read 2 more answers
Mal spends 7 hours in school each day. Her lunch period is 1 hour long, and she spends a
Alex787 [66]

Answer:

z = 5*(1/2)

z = 5/10

---

time switching classes:

w = 7/10

---

y - 6x - z - w = 0

6x = y - z - w

x = (y - z - w)/6

x = (76/10 - 5/10 - 7/10)/6

x = (76 - 5 - 7)/(10*6)

x = (64)/(10*6)

x = (2*2*2*2*2*2)/(2*5*2*3)

x = (2*2*2*2)/(5*3)

x = 16/15

x = 1.0666666666

---

check:

y = 7 + 3/5

y = 7.6

z = 1/2

z = 0.5

w = 7/10

w = 0.7

y - 6x - z - w = 0

6x = y - z - w

x = (y - z - w)/6

x = (7.6 - 0.5 - 0.7)/6

x = 1.0666666666

---

answer:

z = 5*(1/2)

z = 5/10

---

time switching classes:

w = 7/10

---

y - 6x - z - w = 0

6x = y - z - w

x = (y - z - w)/6

x = (76/10 - 5/10 - 7/10)/6

x = (76 - 5 - 7)/(10*6)

x = (64)/(10*6)

x = (2*2*2*2*2*2)/(2*5*2*3)

x = (2*2*2*2)/(5*3)

x = 16/15

x = 1.0666666666

---

check:

y = 7 + 3/5

y = 7.6

z = 1/2

z = 0.5

w = 7/10

w = 0.7

y - 6x - z - w = 0

6x = y - z - w

x = (y - z - w)/6

x = (7.6 - 0.5 - 0.7)/6

x = 1.0666666666

---

answer:

each class is 1.07 hours

Step-by-step explanation:

8 0
2 years ago
The vector ~v represents the displacement vector from Portland, Oregon to Houston, Texas. The vector w~ represents the displacem
Art [367]

Answer:

a

the displacement of the plane is  - \= w

b

The displacement of plane  from Portland to Akron with layover at Houston is  

       \= v  + \= w

c

  the vector which defines this displacement is  \= v + \= w  =- 2500 \ km

Step-by-step explanation:

From the question we are the

   The displacement from Portland, Oregon to Houston, Texas. is  \= v

    The displacement  from Houston, Texas to Akron, Ohio.  is \= wa

a

   The motion of the plane in question a is in the opposite direction to vector \= w

So the displacement of the plane is  - \= w

b

The motion of Portland to Houston to Akron is in the direction of both vector \= v and  \= w  so

The displacement of plane  from Portland to Akron with layover at Houston is  

       d =  \= v  + \= w

c

From the question we are told that the plane flies over Portland to get to  Anchorage, Alaska which implies that it is moving in opposite direction to the vector \= v

   Give that distance from Portland to Houston is  \= v  = 3000 km

           and the distance from Portland to  Anchorage is \= w = - 5500km

Then the vector which defines this displacement is mathematically represented as

   \= v + \= w  = 3000  -5500

    \= v + \= w  =- 2500 \ km

       

4 0
3 years ago
Solve question 13. And 14. Please!! Will reward brainliest!!
SIZIF [17.4K]

Answer:

y = 4 sin( 0.5t - \frac{4\pi }{3} ) - 2

y = a sin ( 2t - \frac{-\pi }{3}) + 2

Step-by-step explanation:

In the first question,

amplitude = 4

Period = 4\pi

phase shift = \frac{-4\pi }{3}

Vertical shift = -2

Angular velocity , w = \frac{2\pi }{time period}

Here, w = \frac{2\pi }{4\pi } = 0.5

The general equation of a wave is

y = a sin( wt + ∅ )

Putting above values in the equation,

y = 4 sin( 0.5t - \frac{4\pi }{3} ) - 2

In the second question,

Amplitude is not given so we will take it as a.

time period = \pi

w = 2

Phase shift = \frac{-\pi }{3}

Vertical shift = 2

The equation is

y = a sin ( 2t - \frac{-\pi }{3}) + 2

5 0
3 years ago
How would knowing the type of symmetry help you graph a function?
Serga [27]

A graph is said to be symmetric about the y -axis if whenever (a,b) is on the graph then so is (−a,b) . Here is a sketch of a graph that is symmetric about the y -axis. A graph is said to be symmetric about the origin if whenever (a,b) is on the graph then so is (−a,−b) .

hope this helped u <3

4 0
3 years ago
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