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3 years ago

Factor b2 + b – 6.

Mathematics

1 answer:

Ulleksa [173]3 years ago

6 0

The answer is A,(b + 3)(b - 2)

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Which of the following sets of numbers could not represent the three sides of a right

mario62 [17]

Answer:

The answer is (13,48,50)

5 0

3 years ago

Integrate this two questions

tankabanditka [31]

Simplify the integrands by polynomial division.

$\dfrac{t^2}{1 - 3t} = -\dfrac19 \left(3t + 1 - \dfrac1{1 - 3t}\right)$

$\dfrac t{1 + 4t} = \dfrac14 \left(1 - \dfrac1{1 + 4t}\right)$

Now computing the integrals is trivial.

$\displaystyle \int \frac{t^2}{1 - 3t} \, dt = -\frac19 \int \left(3t + 1 - \frac1{1-3t}\right) \, dt \\\\ = -\frac19 \left(\frac32 t^2 + t + \frac13 \ln|1 - 3t|\right) + C \\\\ = \boxed{-\frac{t^2}6 - \frac t9 - \frac{\ln|1-3t|}{27} + C}$

where we use the power rule,

$\displaystyle \int x^n \, dx = \frac{x^{n+1}}{n+1} + C ~~~~ (n\neq-1)$

and a substitution to integrate the last term,

$\displaystyle \int \frac{dt}{1-3t} = -\frac13 \int \frac{du}u \\\\ = -\frac13 \ln|u| + C \\\\ = -\frac13 \ln|1-3t| + C ~~~ (u=1-3t \text{ and } du = -3\,dt)$

$\displaystyle \int \frac t{1+4t} \, dt = \frac14 \int \left(1 - \frac1{1+4t}\right) \, dt \\\\ = \frac14 \left(t - \frac14 \ln|1 + 4t|\right) + C \\\\ = \boxed{\frac t4 - \frac{\ln|1+4t|}{16} + C}$

using the same approach as above.

5 0

2 years ago

HELP NOwwwwWWWW ILL GIVE BRAINLIEST

Elza [17]

Answer: -7/3

Step-by-step explanation:

Perpendicular lines have slopes that are negative reciprocals of each other.

6 0

2 years ago

PLEASE HELPPPPPPPPPPPP ME! THANK YOU!

Ainat [17]

Answer:

x=0

x=10

x=24

Step-by-step explanation:

f(x) = -.05x^2 + x +6

The initial value is 6 ( Let x=0 and f(0) = 6)

f(x) = -.05( x^2 -20 x -120)

I plotted the equation and maximum is at x=10 and the zero is at x=25

3 0

3 years ago

The axis of symmetry for the graph of the function f(x)=3x2+bx+4 is x3/2. What is the value of b

Alexxandr [17]

Answer:

uhm it should be b=x5/2

Step-by-step explanation:

7 0

3 years ago