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What conic section degenerates into a line?

andrew11 [14]

<h3>Answer: A) parabola</h3>

Some degenerate parabola cases form a single straight line, while other cases form one pair of parallel lines.

A degenerate hyperbola forms two lines that intersect at the vertex of the cone. We can rule out choice B.

A degenerate circle is a single point, so we can rule out choice C.

A degenerate ellipse is also a single point. Any circle is an ellipse (but not the other way around). We can rule out choice D.

5 0

3 years ago

: A personal computer manufacturer buys 36% of its chips from Japan and the rest from the United St...

meriva

Answer: 0.9862

Step-by-step explanation:

Given : The probability that the chips belongs to Japan: P(J)= 0.36

The probability that the chips belongs to United States : P(U)= 1-0.36=0.64

The proportion of Japanese chips are defective : P(D|J)=0.017

The proportion of American chips are defective : P(D|U)=0.012

Using law of total probability , we have

$P(D)=P(D|J)\times P(J)+P(D|U)\times P(U)\\\\\Rightarrow\ P(D)=0.017\times0.36+0.012\times0.64=0.0138$

Thus , the probability that chip is defective = 0.0138

Then , the probability that a chip is defect-free= $1-0.0138=0.9862$

3 0

3 years ago

Solve x-15=8 Help! Thank you!

Bezzdna [24]

x-15 = 8

add 15 to each side

x = 23

3 0

3 years ago

Read 2 more answers

Find the exact value of tan (arcsin (two fifths)). For full credit, explain your reasoning.

Hitman42 [59]

$\bf sin^{-1}(some\ value)=\theta \impliedby \textit{this simply means}
\\\\\\
sin(\theta )=some\ value\qquad \textit{now, also bear in mind that}
\\\\\\
sin(\theta)=\cfrac{opposite}{hypotenuse}\qquad 
\qquad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\\\\
-------------------------------\\\\$

$\bf sin^{-1}\left( \frac{2}{5} \right)=\theta \impliedby \textit{this simply means that}
\\\\\\
sin(\theta )=\cfrac{2}{5}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{now let's find the adjacent side}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}$

$\bf \pm \sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a
\\\\\\
\textit{we don't know if it's +/-, so we'll assume is the + one}\quad \sqrt{21}=a\\\\
-------------------------------\\\\
tan(\theta)=\cfrac{opposite}{adjacent}\qquad \qquad tan(\theta)=\cfrac{2}{\sqrt{21}}
\\\\\\
\textit{and now, let's rationalize the denominator}
\\\\\\
\cfrac{2}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{2\sqrt{21}}{(\sqrt{21})^2}\implies \cfrac{2\sqrt{21}}{21}
$

7 0

3 years ago

The function f(x) = 1.50x + 12.50 relates how much kelsey pays for digital service, f(x), to the number of movies, x, she stream

Brums [2.3K]

f(18) = 39.50

This gives the monthly cost Kelsey will pay if she streams 18 movies in a month

Step-by-step explanation:

Given function is:

$f(x) = 1.50x+12.50$

Here x is the number of movies

so for f(18), this means that the total number of movies will be 18

Solving

$f(18) = 1.50(18)+12.50\\f(18) = 27+12.50\\f(18) = 39.50$

Hence,

f(18) = 39.50

This gives the monthly cost Kelsey will pay if she streams 18 movies in a month

Keywords: functions, Domain,range

Learn more about functions at:

#LearnwithBrainly

6 0

3 years ago

Can you help thanks ​

Can you help thanks