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Hunter-Best [27]
3 years ago
15

Is 307,404 divisible by 3?​

Mathematics
1 answer:
SVEN [57.7K]3 years ago
6 0
ANSWER:
No, neither is devisible by 3
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The pinata weighs 11/4 pounds without candy.He adds 8bags that weighs 3/8,3/8,1/2,1/2,1/2,3/4,3,11/4 how much will the pinata we
Natalka [10]

Answer:

Weight = \frac{23}{2}

Step-by-step explanation:

Given

Weight of Pinata = 11/4 lb

Weight of candies = 3/8, 3/8, 1/2 , 1/2, 1/2, 3/4, 3, 11/4

Required

Weight of Pinata when filled with candies

To solve this question, we simply need to add all weights together

First, we need to add up the weight of the candies

Candies =  \frac{3}{8} + \frac{3}{8} + \frac{1}{2}+ \frac{1}{2}+ \frac{1}{2}+ \frac{3}{4} + 3 + \frac{11}{4}

Take LCM

Candies = \frac{3 + 3 + 4 +4 + 4 + 6 + 24 + 22}{8}

Candies = \frac{70}{8}

Simplify:

Candies = \frac{35}{4}

Next; Add the weight of the candies to the weight of pinata

Weight = Candies + Pinata

Weight = \frac{35}{4} + \frac{11}{4}

Take LCM

Weight = \frac{35 + 11}{4}

Weight = \frac{46}{4}

Simplify

Weight = \frac{23}{2}

<em>Hence, the weight of the Pinata after it is filled with candies is 23/2 lb</em>

4 0
4 years ago
Is a rectangle with curved angles a polygon
Alik [6]
A polygon must have at least 3 sides, but a curved angle isn't a side. This would result in you getting an oval. In short, it would not be a polygon. Hope this helps!
3 0
4 years ago
Find the length of “b”, to the<br> nearest tenth, using the<br> Pythagorean Theorem.
Tresset [83]

Answer: b= 11.2

10^2 + b^2 = 15^2

100 + b^2 =  225

b^2 = 125

b= \sqrt{125}

b= 11.2

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Factor.<br> 28 - 4u<br> I don’t know how to factor 28-4u so if anyone can help thank you
Sedaia [141]

Answer: 4(7-u)

Step-by-step explanation:

In order to factor, you have to find the GCF (Greatest Common Factor)

28:1, 28, 2, 14, 4, 7

4:1, 4, 2

The greatest common factor here is 4.

You can factor out 4 from this equation, therefore making it 4(7-u)

3 0
3 years ago
Maria throws a softball straight up into the air with an initial velocity of 50 ft/sec. The ball leaves her hand when it is exac
Nataly_w [17]

Answer:

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

Step-by-step explanation:

Let suppose that effects from air friction and Earth's rotation can be neglected, so that the softball can be modelled experiment a free fall, that is, an uniform accelerated motion due to gravity. From we know the initial velocity and position of the position and we can determine the final position of the ball as a function of the final velocity:

v_{f}^{2} = v_{o}^{2}+2\cdot a \cdot (s_{f}-s_{o}) (1)

Where:

s_{o}, s_{f} - Initial and final position of the softball, measured in feet.

a - Acceleration, measured in meters per square second.

v_{o}, v_{f} - Initial and final velocities of the softball, measured in feet per second.

If we know that v_{o} = 50\,\frac{ft}{s}, a = -32.174\,\frac{m}{s^{2}} and s_{o} = 4\,ft, then the equation that models the situation is:

v_{f}^{2} = 2500-64.348\cdot (s_{f}-4)

Then, we clear the final position of the softball:

-\frac{v_{f}^{2}-2500}{-64.348} = s_{f}-4

s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

8 0
3 years ago
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