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dolphi86 [110]
2 years ago
13

Will choose Brainliest.

Mathematics
1 answer:
oksano4ka [1.4K]2 years ago
4 0

That part is total cookies as per algebraic formula x^2-(a+b)x+ab=0

Hence

The inequality is

\\ \rm\rightarrowtail x^2-30x+224>=0

\\ \rm\rightarrowtail (x-14)(x-16)>=0

\\ \rm\rightarrowtail 14\leqslant x\leqslant 16

Solution range

  • [14,16]

Atleast means the range

  • 16-14
  • 2

Atleast 2 more than Martha

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3,600<br> The square roots are<br> and
ehidna [41]

Answer:

60

Step-by-step explanation:

60x60=3,600

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3 years ago
Please Help....................................
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The answer are:
(-4,5)

(2,2)
 
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(2,-1)

(-5,6)
5 0
3 years ago
Y≥−2x−8<br><br> What is the answer?
Crank

Answer: Here Take a Look.

Resources I Used: Mhway and or Browsing List.

(I Do Claim To Own Any Of This Information Provided For More Resources and Results Consult a Math Tutor Or ask me for Help Id be Happy To With Anything at Any Time. Product of 2022 Distribution)

Step-by-step explanation:

5 0
2 years ago
Suppose 60% of American adults believe Martha Stewart is guilty of obstruction of justice and fraud related to insider trading.
Ierofanga [76]

Answer:

Since the sample size is large enough (n>30) and the probability of success is near to 0.5, and we have that n\hat p = 60>10 and n(1-\hat p) = 40>10 we can assume that the distribution for \hat p is normal

The population proportion have the following distribution  

\hat p \sim N(\hat p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

The mean is given by:

\mu_p = 0.6

\sigma_p = \sqrt{\frac{0.6*(1-0.6)}{100}}=0.04899

So then we can conclude that the best answer would be:

c. approximately Normal, with mean 0.6 and standard error 0.04899

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

p represent the real population proportion of interest

\hat p represent the estimated proportion for the sample

n is the sample size required (variable of interest)

Solution to the problem

Since the sample size is large enough (n>30) and the probability of success is near to 0.5, and we have that n\hat p = 60>10 and n(1-\hat p) = 40>10 we can assume that the distribution for \hat p is normal

The population proportion have the following distribution  

\hat p \sim N(\hat p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

The mean is given by:

\mu_p = 0.6

\sigma_p = \sqrt{\frac{0.6*(1-0.6)}{100}}=0.04899

So then we can conclude that the best answer would be:

c. approximately Normal, with mean 0.6 and standard error 0.04899

8 0
3 years ago
HELPPPPPP ASAPPPPPP PLEASEEE
qwelly [4]

Answer:

here

Step-by-step explanation:

-3,3

2,3

3,3

4,3

I hope this helped! :D

6 0
3 years ago
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