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kolbaska11 [484]
3 years ago
8

Which of the following statements shows the inverse property of addition?

Mathematics
2 answers:
andrew-mc [135]3 years ago
5 0
Y+(-y)=0, because the Inverse property states that a number added to it's inverse equal 0.
mario62 [17]3 years ago
5 0

Answer:

The statement y + (-y) = 0 shows the inverse property of addition

Step-by-step explanation:

The inverse property of addition states that any number y, that is added to its inverse number - y will give as a result 0. This is exactly what shows statement A : y + (-y) = 0

Statement B states the Identity property where any number which we add 0 gives the original number. The statament c is the Multiplication by one property where any number multiplied by 1 gives the original number, the variation of identity property of addition, and D is only  a normal addition.

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Algebra 1 polynomials hellllp​
defon
A. 40x^2 + 240x + 200
Shape: Rectangle
Formula: A = LW
A = (10x + 10)(4x + 20)
= (10x)(4x) + (10x)(20) + (10)(4x) + (10)(20)
= 40x^2 + 200x + 40x + 200
= 40x^2 + 240x + 200
————————————————————-
2. 57,600 ft^2
Width:
4x + 20 = 160
4x = 140
x = 35
Plug-In:
10x + 10
10(35) + 10
350 + 10
360 = Length
————————————-
A = LW
A = 360 • 160
A = 57,600 ft^2
8 0
2 years ago
Help please <br><br>number 4, 5, 6, and 7​
FinnZ [79.3K]

Step-by-step explanation:

4. So, total time traveled is calculated by adding travel times in both directions.

From Detroit to Chicago, Charlie flew 300 miles at 150 miles per hour speed. That means that he traveled:

t1 = s / v1

t1 = 300 miles / 150 miles per hour

t1 = 2 hours

Now, let's do the same for the opposite direction. Since it's the same distance, he again flew 300 miles, but the speed this time was 100 miles per hour:

t2 = s / v2

t2 = 300 miles / 100 miles per hour

t2 = 3 hours

So, total time he traveled was t1 + t2 = 2 hours + 3 hours = 5 hours.

For the trip distance we need to add distances in both directions. We already said that the distance is the same, so the total trip distance is 300 miles + 300 miles = 600 miles.

Displacement shows how far are the ending and the starting point. Since Charlie started from Detroit, flew to Chicago, and then came back to Detroit, his ending point is the same as the starting, so the displacement is 0.

We can calculate average speed by dividing total distance with the total travel time. We already found that the total trip distance was 600 miles, and the total travel time was 5 hours. That means that:

v(average) = s(total) / t (total)

v(average) = 600 miles / 5 hours

v (average) = 120 miles per hour

As for the average velocity, we calculate it by dividing displacement by total travel time. Since the displacement was 0, average velocity will also be 0.

5. From the left graph we see that the object went from 0 to 2 meters (it moved 2 meters) in 1 second. That means that its speed was:

v1 = s1 / t1

v1 = 2 meters / 1 second

v1 = 2m/s

From there, it went from 2 to 4 meters (it moved 2 meters) in the next 4 seconds. That means that its speed, during that interval, was:

v2 = s2 / t2

v2 = 2 meters / 4 seconds

v2 = 0.5 m/s

So, our graph will show, for the first second, velocity of 2m/s, and for the next four seconds, the velocity of 0.5 m/s.

6. Again, when calculating speed, we use the equation:

v = s / t

In this case, the distance (s) is 325 miles and the time (t) is 5 hours. So, the speed will be:

v = 325 miles / 5 hours

v = 65 mph

7. Now, we have the same distance (s) of 325 miles ant the speed (v) of 70 mph. We want know how long will the drive take:

t = s / v

t = 325 miles / 70 mph

t = 4.64 hours.

6 0
3 years ago
9 + 5 = x - 11<br>how to find the x number
astra-53 [7]

9 + 5 = x - 11

combine like terms

14 = x - 11

add 11 to both sides

25 = x

or

x = 25

answer

x = 25

5 0
3 years ago
Read 2 more answers
How many integers between 10000 and 99999, inclusive, are divisible by 3 or<br> 5 or 7?
Yuki888 [10]

Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

Step-by-step explanation:

Since we have given that

Integers between 10000 and 99999 = 99999-10000+1=90000

n( divisible by 3) = \dfrac{90000}{3}=30000

n( divisible by 5) = \dfrac{90000}{5}=18000

n( divisible by 7) = \dfrac{90000}{7}=12857.14

n( divisible by 3 and 5) = n(3∩5)=\dfrac{90000}{15}=6000

n( divisible by 5 and 7) = n(5∩7) = \dfrac{90000}{35}=2571.42

n( divisible by 3 and 7) = n(3∩7) = \dfrac{90000}{21}=4285.71

n( divisible by 3,5 and 7) = n(3∩5∩7) = \dfrac{90000}{105}=857.14

As we know the formula,

n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)

=30000+18000+12857.14-6000-2571.42-4258.71+857.14\\\\=48884.15

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

5 0
4 years ago
Anyone pls help on this
Tatiana [17]
(Exponential decay) hope it helps:)
4 0
3 years ago
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