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PilotLPTM [1.2K]
2 years ago
12

Someone Help please!

Mathematics
1 answer:
salantis [7]2 years ago
8 0
I think ur answer would be C.
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Please please help
777dan777 [17]

Step-by-step explanation:

Statement. Reason

→ 9(x-6)+41 = 75. Transposing the like terms.

→ 9(x-6) = 75 - 41 Performing subtraction of the term in RHS

→ 9(x-6) = 34 Performing multiplication in LHS.

→ 9x - 54 = 34 Distributive property

→ 9x = 34 + 54 Performing addition of the term in RHS.

→ 9x = 88. Now, transpose 9 from LHS to RHS , it's arthmetic operator will get changed.

→ x = 88/9

6 0
2 years ago
The store manager ordered402 baseball caps and 122 ski caps. Estimate the total numbers of caps the manager ordered
Leni [432]
520 is the estimated answer
5 0
3 years ago
Does anyone get this? <br> The answers are <br> A - 22.8 <br> B - 25.5 <br> C - 14.1<br> D - 31.2
Rom4ik [11]

Answer:

Step-by-step explanation:

I think your supposed to add all those numbers together

5 0
3 years ago
Read 2 more answers
I don’t understand how to do this
schepotkina [342]

Answer:

The solution is x =0.

Step-by-step explanation:

The equation

\bold{(1).}\: sin(\dfrac{3\pi }{2} +x)+sin(\dfrac{3\pi }{2} +x) =-2

can be rewritten as

2* sin(\dfrac{3\pi }{2} +2) =-2

and can be further simplified to

sin(\dfrac{3\pi }{2}+x ) =-1.

Now, taking the inverse sine of both sides we get:

sin^{-1}(sin(\dfrac{3\pi }{2} +x) =sin^{-1}(-1)

\bold{(2).}\:  \dfrac{3\pi }{2} +2 =sin^{-1}(-1)

The value of the right side on the interval [0,2\pi) is

sin^{-1}(-1) = \dfrac{3\pi}{2} \: \:( \text{or }270^o) ,

which makes the equation (2)

\dfrac{3\pi }{2}+x  =\dfrac{3\pi}{2}

solving for x gives

\boxed{x = 0}

which is our solution.

4 0
3 years ago
PLEASE GUYS HELP ME I NEED THIS FOR A TEST NOW
ValentinkaMS [17]

Answer:

23.54 m

Step-by-step explanation:

Applying

cos∅ = adjacent(A)/hypotenuse(H)

cos∅ = A/H................ Equation 1

make H the subject of the equation

H = A/cos∅............ Equation 2

Given: A = 15 m, ∅ = 25°

Substitute into equation 2

H = 15/cos25

H = 16.55 m

Also,

tan∅ = opposite(O)/Adjacent(A)

tan∅ = O/A............Equation 3

Make O the subject of the equation

O = Atan∅.......... Equation 4

Substituting into equation 4

O = 15(tan25°)

O = 6.99 m.

From the diagram,

The height of the goal post before snap = H+O

The height of the goal post before snap = 16.55+6.99

The height of the goal post before snap = 23.54 m

4 0
2 years ago
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