(Problems 1b and 2b are cut off in the photo)
1a Problem:
(-3,1)
(-3,5)
(-7,1)
2a Problem:
(6,2)
(3,5)
(10,7)
*Psst, I need one more brainliest answer to rank up, so if you gave that to me, it would be very appreciated, thanks :)*
Answer:
Step-by-step explanation:
Total number of antenna is 15
Defective antenna is 3
The functional antenna is 15-3=12.
Now, if no two defectives are to be consecutive, then the spaces between the functional antennas must each contain at most one defective antenna.
So,
We line up the 13 good ones, and see where the bad one will fits in
__G __ G __ G __ G __ G __G __ G __ G __ G __ G __ G __ G __G __
Each of the places where there's a line is an available spot for one (and no more than one!) bad antenna.
Then,
There are 14 spot available for the defective and there are 3 defective, so the arrange will be combinational arrangement
ⁿCr= n!/(n-r)!r!
The number of arrangement is
14C3=14!/(14-3)!3!
14C3=14×13×12×11!/11!×3×2
14C3=14×13×12/6
14C3=364ways
Answer:
T=N*M and he needs to read 44 books.
Step-by-step explanation:
Note: Let T represent the total amount of books that Alan needs to read in 11 months.
If we plug in the information we have been given we will find the total:
T=N*M
T=4*11
T=44
Alan has to read 44 books within a 11 month period.
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Answer:
99,900
Step-by-step explanation:
