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3 years ago

2m-5=17 I need an step by step explanation

Mathematics

2 answers:

Iteru [2.4K]3 years ago

6 0

Answer: m=11

Step-by-step explanation:

First since there are no m's on the other side you cancel out the 5 by adding 5 to -5 and then add 5 to 17 which will give you 22

2m-5=17

+5 +5

2m=22

Now you divide 2m by to get the variable m by itself then divide the other side by 2

2m=22

÷2. ÷2

Which leaves you with

M=11

Snezhnost [94]3 years ago

5 0

Answer: m = 11

Step-by-step explanation:

In order to solve this equation, you have to bring the 5 to the 17. To cancel out the -5 add a five. Then do that to 17. Now you have 2m = 22. To isolate m, divide. 2m divided by 2 is m, and 22 divided by 2 is 11. M = 11.

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drek231 [11]

Answer:

A sample of $n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2$ is needed, in which E is the desired margin of error, as a proportion. If we find a decimal value, we round up to the next whole number.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In a previous study of 1012 randomly chosen respondents, 374 said that there should be such a law.

This means that $n = 1012, \pi = \frac{374}{1012} = 0.3696$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

How large a sample size is needed to be 95% confident with a margin of error of E?

A sample size of n is needed, and n is found when M = E.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$E = 1.96\sqrt{\frac{0.3696*0.6304}{n}}$

$E\sqrt{n} = 1.96\sqrt{0.3696*0.6304}$

$\sqrt{n} = \frac{1.96\sqrt{0.3696*0.6304}}{E}$

$(\sqrt{n})^2 = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2$

$n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2$

A sample of $n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2$ is needed, in which E is the desired margin of error, as a proportion. If we find a decimal value, we round up to the next whole number.

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