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2 years ago

8

Alexa is ordering a taxi from an online taxi service. The taxi charges $4 just for the pickup and then an additional $1.25 per m

ile driven. How much would a taxi ride cost if Alexa is riding for 9 miles? How much would a taxi ride cost that is mm miles long?

1 answer:

Anvisha [2.4K]2 years ago

8 0

Answer:$15.25

Step-by-step explanation:just multiply $1.25x9 then add 4

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max2010maxim [7]

Hello!

So, this is quite the complex question, and here are the following steps:

What is the quotient of $\frac{6-3\sqrt[3]{6}}{\sqrt[3]{9}}$ ?

$\frac{(6 - 3\sqrt[3]{6})\sqrt[3]{9^{2}}}{9}$ (rationalize the denominator)

$\frac{3(2 -\sqrt[3]{6})\sqrt[3]{9^{2}}}{9}$ (factor 3 from the expression)

$\frac{(2-\sqrt[3]{6})\sqrt[3]{9^{2}}}{3}$ (reduce the fraction with 3)

$\frac{2\sqrt[3]{9^{2}}-\sqrt[3]{9^{2}}}{3}$ (distributive property)

$\frac{2\sqrt[3]{81}-\sqrt[3]{486}}{3}$ (simplify 3 · 9²)

$\frac{6\sqrt[3]{3}-3\sqrt[3]{18}}{3}$ (simplify the radical)

$\frac{3(2\sqrt[3]{3}-3\sqrt[3]{18})}{3}$ (factor 3 from the expression)

$2\sqrt[3]{3}-\sqrt[3]{18}$ (reduce the fraction)

The answer, is simply, choice A, $2\sqrt[3]{3} -\sqrt[3]{18}$ ≈ 0.263758.

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3 years ago

Which graph shows the solution to this system of inequalities?<br> y < 2x + 4<br> y > -X -3

Arturiano [62]

Answer:

The answer is Graph X.

Always start by isolating the variable \color{red}y on the left side of the inequality.
Change the inequality to equality symbol.
Graph the boundary line from step 2 in the XY-plane.
The last step is to shade one side or region of the boundary line.

Please Mark Brainliest If This Helped!

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Darina [25.2K]

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aw, i <3 you to ;)

if you need me let me know

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the vertex of this parabola is at (3,5). When the y-value is 6, the x-value is -1. What is the coefficient of the squared term i

otez555 [7]

Now, assuming is a vertical parabola, so the squared variable is the "x", let's do some checking.

$\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
vertex
\begin{cases}
h=3\\
k=5
\end{cases}\implies y=a(x-3)^2+5
\\\\\\
\textit{we also know that }
\begin{cases}
y=6\\
x=-1
\end{cases}\implies 6=a(-1-3)^2+5
\\\\\\
1=a(-4)^2\implies 1=16a\implies \cfrac{1}{16}=a$

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andriy [413]

Answer:

Its B

Step-by-step explanation:

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