Answer:
Four (4)
Explanation:
Two ATP molecules are required to start glycolysis (from glucose), and four are generated by substrate-level phosphorylation. An additional two NADH molecules are generated, which can be used to generate another three to five ATP molecules through the electron transport chain in the mitochondria.
In order to find the percentage of the litters that will consist of two wavy- haired and three straight-haired offspring, you need to use the binomial distribution formula: P(x) = ⁿCₓ × pₓ × qⁿ⁻ˣ
P is the probability that the litters will consist of two wavy-haired and three straight-haired offspring.
X is considered to be the number of times the offspring will have wavy-air in a litter of 5 offspring, which is 2.
n is the number of offspring per litter.
p is the probability of happening wavy hair.
q is the probability of having straight hair.
It comes like this:
P(X=2)=⁵C₂×0.5²×0.5⁵⁻² ⇔ P(X=2)=10×0.25×0.125 ⇔ P(X=2)=0.3125
So, the percentage of the litters that will consist of two wavy-haired and three straight-haired offspring is 31.25%.
<span> ORGANELLEs are structures within a cell that have particular jobs to do in the cell</span>
Answer:
Anaphase would be the correct answer. So you know anaphase is the shortest phase of mitosis; because literally all that happens is chromatids are pulled to polar opposite sides of the cell. All the work for this phase is completed in metaphase when spindle fibers (microtubules) grow from the centrioles and bind to the kinetochores of the chromosome.
