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Alexxandr [17]
2 years ago
11

(b) Identify the dependent variable in the experiments. Identify a control group missing from the second experiment. Justify the

need for this control group in the second experiment.
Biology
1 answer:
hammer [34]2 years ago
4 0

Hello. You have not submitted the experiments to which this question refers, which makes it impossible for it to be answered. However, I will try to help you in the best possible way.

A dependent variable is one that is influenced by an element, in order to present a result, that is, it is a variable that does not establish itself, being dependent on another variable to establish itself. An example of a dependent variable can be seen in an experiment that seeks to determine the differences in growth rates of bean plants that were fertilized with different organic fertilizers. As you can see, this is an experiment where the different organic fertilizers influence differences in the growth rate of bean plants. Thus, the growth of these plants depends on the fertilizer, this growth being the variable dependent on the experiment.

A control group, in turn, is an element of the experiment that does not receive the element that is being tested in the same experiment. The control group is important, because it allows the researcher to see the results of a system where the tested element does not exist, thus being able to determine the real differences that the tested element is capable of causing. Using the same example presented in the paragraph above, we can see that the different organic fertilizers are the elements tested in the experiment. These fertilizers will be applied to the plants, however it is important that at least one of these plants does not receive any fertilizer, so that the difference between a system with fertilizer and a system without fertilizer can be evaluated. This plant that received no fertilizer is the control group.

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Given;
            x + y + z = 140 meters


According to the proportion theorem,

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Solving for x, using cross multiplication:

\frac{x}{1} = \frac{40y}{30}

Similarly,

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solving for z by cross multiplication,

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Now, the third proportions,
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Solving for y,

y = 30z/35
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224y + 144z + 147x = 23520

Substitutoing z = 7x/8,

224y + (144 × 7x/8) + 147x = 23520

224y + 126x + 147x = 23520

224y + 273x = 23520
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Substitute y = 3x/4

(224×3x/4) + 273x = 23520

168x + 273x = 23520

441x = 23520

x = 53.33

Now,
We know that
y = 3x/4
so,
y = 40

And,
z = 7x/8
Z = 46.66

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