To solve this problem, we make use of the Binomial
Probability equation which is mathematically expressed as:
P = [n! / r! (n – r)!] p^r * q^(n – r)
where,
n = the total number of gadgets = 4
r = number of samples = 1 and 2 (since not more than 2)
p = probability of success of getting a defective gadget
q = probability of failure = 1 – p
Calculating for p:
p = 5 / 15 = 0.33
So,
q = 1 – 0.33 = 0.67
Calculating for P when r = 1:
P (r = 1) = [4! / 1! 3!] 0.33^1 * 0.67^3
P (r = 1) = 0.3970
Calculating for P when r = 2:
P (r = 2) = [4! / 2! 2!] 0.33^2 * 0.67^2
P (r = 2) = 0.2933
Therefore the total probability of not getting more than
2 defective gadgets is:
P = 0.3970 + 0.2933
P = 0.6903
Hence there is a 0.6903 chance or 69.03% probability of
not getting more than 2 defective gadgets.
Take a look at the picture i sent you
Answer:
95 ; 105
Step-by-step explanation:
Let :
Aanya's time = x
Krish's time = x + 10
Together = 50
Hence
Aanya's rate = 1/x
Krish's rate = 1/(x + 10)
Together rate = 1/50
Hence,
1/x + 1/(x + 10) = 1 / 50
((x + 10) + x) / x(x + 10) = 1/ 50
(2x + 10)/ x² + 10x = 1/50
50(2x + 10) = x² + 10x
100x + 500 = x² + 10x
x² + 10x - 100x - 500 = 0
x² - 90x - 500 = 0
Using the quadratic equation solver :
x = 95.24 ; x = - 5.24
Time can't be negative
Hence, x = 95 (nearest minute)
It takes Aanya 95 minutes Alone a ND
Krishna (95 + 10) = 105 minutes alone
You need to show us the bar model
