A person runs 1/ 4/5 miles i n 1/5 of and hour how many miles they are running per hour

The water level of a certain body of water is changing at a rate of W(t)=3/4cos(4-t/2) inches per hour, where t represents hours

Leni [432]

Answer:

The answer is below

Step-by-step explanation:

a) The integral $\int\limits^{10}_{1 } {W(t)} \, dt$ means the total change in level of water in inches from 1 am to 10 am. That is the water level change measured in inches between 1 am and 10 am

b) 7 pm is represented as t = 19 hours, while midnight is represented as t = 24 hours, hence the water level change between 7 pm and midnight is:

$\int\limits^{24}_{19 } {W(t)} \, dt\\\\$

c) Using casio calculator to evaluate the integral gives:

$\int\limits^{24}_{19 } {W(t)} \, dt\\\\$ = 2.54 inches

D) The total daily change in water level = $\int\limits^{24}_{0 } {W(t)} \, dt\\\\$ = 0.35 inches

8 0

3 years ago

Mr. Malone is contemplating which chauffeured car service to take to the airport. The first costs $28 upfront and $2 per mile. T

Ksju [112]

Answer:

The distance is 8 miles.

Step-by-step explanation:

First, we need to write an equation for each of chauffeured car services.

The first one = 28 + 2x = ?

The second one = 13 + 5x = ?

Next, we need to figure out what x is. Usually I just plug in random numbers, but I'm sure there's a better way to do it.

I first plugged in 2 as x.

28 + 4 = 32

13 + 10 = 23

That didn't work, so I then plugged in 5.

28 + 10 = 38

13 + 25 = 38

So 5 would be the correct answer for what is the distance.

8 0

3 years ago

Find the compunt intrest on rs 31250 at 12 % per annum for 12 1/2 years

postnew [5]

Answer:

Step-by-step explanation:

given Principle at 31250

and rate = 12%

and time 12.5 years

the amount would be given by the equation

$P(1+\frac{rate}{100})^{time}$

plug in values to get

$31250(1+\frac{12}{100})^{12.5}$

end up with value $128847

3 0

2 years ago

The present age of father is thrice as old as the age of daughter 5 years ago. If 5 years hence ,the age of father will be twice

pav-90 [236]

Answer:

Hence the daughter's present age is 15 years

The fathers present age is 35 years

Step-by-step explanation:

Let the present age of daughter be x

Let the present age of father be y

5 years ago;

Daughter's age = x - 5

Fathers age = y - 5

If the present age of father is thrice as old as the age of daughter 5 years ago, then;

y - 5 = 3(x-5)

y - 5 = 3x-15

y = 3x - 10 .... 1

In 5 years time;

Daughters age = x + 5

Fathers age = y + 5

If the age of father will be twice the age of his daughter in 5 years time then;

y+5 = 2(x+5)

y+5 = 2x + 10

y = 2x + 5 .....2

Equate 1 and 2;

3x - 10 = 2x + 5

3x - 2x = 5 + 10

x = 15

Since y = 2x + 5

y = 2(15) + 5

y = 35

Hence the daughter's present age is 15 years

The fathers present age is 35 years

3 0

3 years ago

Question Help James and Bethany Morrison are celebrating their 10th anniversary by having a reception at a local reception hall.

BARSIC [14]

What I did was I subtracted 4500 minus 500 because it was a fee then I divide 4400 by 35 and I got 125 people.

3 0

3 years ago

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