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2 years ago

Factor X^2+14n+45. Find the GCF first

Mathematics

2 answers:

makvit [3.9K]2 years ago

7 0

No solution for this problem

Marat540 [252]2 years ago

6 0

Answer:

There is no GCF

Step-by-step explanation:

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Write in scientific notation 0.00042 urgent !!!!

Black_prince [1.1K]

$42 \cdot 10^{-4}$

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2 years ago

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Solve this inequality

8090 [49]

X is greater than or equal to -5

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2 years ago

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A bakery has 2,160 loaves of whole-wheat bread in July. In all, the bakery SOLD 9000 loaves THIS MONTH. What percent of the loav

Bumek [7]

24% because you would make a ratio like x/100= 2,160/9000. So basically the x is the percentage you need, 100 is just an easy factorable percent, and 2,160 is the wheat bread and 9000 is all the bread. Basically what you do with this ratio is you cross multiply. This means you multiply 2,160 by 100 and divide by 9000 and that’s your percent

3 0

3 years ago

1. For the function f(x) = 3x + 1, find f(-2). (substitute -2 in for x)

puteri [66]

Answer:

f(-2) = -5

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Function Notation

Step-by-step explanation:

Step 1: Define

f(x) = 3x + 1

f(-2) is x = -2

Step 2: Evaluate

Substitute in x: f(-2) = 3(-2) + 1
Multiply: f(-2) = -6 + 1
Add: f(-2) = -5

4 0

2 years ago

NASA is conducting an experiment to find out the fraction of people who black out at G forces greater than 6. In an earlier stud

SSSSS [86.1K]

Answer:

The large sample n = 190.44≅190

The large sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44

Step-by-step explanation:

Given population proportion was estimated to be 0.3

p = 0.3

Given maximum of error E = 0.04

we know that maximum error

$M.E = \frac{Z_{\alpha } \sqrt{p(1-p)} }{\sqrt{n} }$

The 85% confidence level $z_{\alpha } = 1.44$

$\sqrt{n} = \frac{Z_{\alpha } \sqrt{p(1-p)} }{m.E}$

$\sqrt{n} = \frac{1.44X\sqrt{0.3(1-0.3} }{0.04}$

now calculation , we get

√n=13.80

now squaring on both sides n = 190.44

large sample n = 190.44≅190

Conclusion:-

Hence The large sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44

7 0

2 years ago