Answer:
1) 3
2) 5
3) 21
4) 57
5) 76
It would be much more easier if there were a grid containing all the numbers.
Answer:
def my_sqrt(a):
while True:
x = a
y = (x + a / x) / 2
if (y == x):
break
else:
x = y
print(x)
return 0
my_sqrt(5)
Explanation:
The above is a function in Python, and the exact copy as code of what is being given in the question. Its a method to find out the square root of a number which is a here. The while loop has been used as being mentioned in the question, and the variables are defined and calculated as being stated.
Answer:
#include <iostream>
using namespace std;
int main() {
int age,time;
float price;
cout<<"Enter age:";
cin>>age;
cout<<"Enter time(in 24 hour clock for noon 1200):";
cin>>time;
if(age>13){
if(time<1700){
price=5;
}else{
price=8;
}
}else{
if(time<1700){
price=2;
}else{
price=4;
}
}
cout<<"Price: $"<<price<<endl;
}
Explanation:
Okay, here are the steps to be taken in order to be able to Write a program that determines the price of a movie ticket as given in details in the question above. Therefore, checked the steps below;
==> Input the age and the time.
==> If the age is not greater than 13, input the time(that is <1700) and follow it by imputing the price.
And if the age is greater than 13, you will also need to input the price. Just as below;
#include <iostream>
using namespace std;
int main() {
int age,time;
float price;
cout<<"Enter age:";
cin>>age;
cout<<"Enter time(in 24 hour clock for noon 1200):";
cin>>time;
if(age>13){
if(time<1700){
price=5;
}else{
price=8;
}
}else{
if(time<1700){
price=2;
}else{
price=4;
}
}
cout<<"Price: $"<<price<<endl;
}
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