The answer:
First: sec(-pi) is sec(pi)
And sec(pi) is -1
Answer:
3(x + 2)(2x - 5)
Step-by-step explanation:
Given
6x² - 3x - 30 ← factor out 3 from each term
= 3(2x² - x - 10) ← factor the quadratic
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term
product = 2 × - 10 = - 20 and sum = - 1
The factors are + 4 and - 5
Use these factors to split the x- term
2x² + 4x - 5x - 10 ( factor the first/second and third/fourth terms )
= 2x(x + 2) - 5(x + 2) ← factor out (x + 2) from each term
= (x + 2)(2x - 5), thus
2x² - x - 10 = (x + 2)(2x - 5) and
6x² - 3x - 30
= 3(x + 2)(2x - 5) ← in factored form
Answer:
2x-32
Step-by-step explanation:
You would distribute the 4.
Answer:
Step-by-step explanation:
AD = DC and BE=EC ⇒
DE = 1/2AB
- 4x + 1 = 1/2(11x - 25)
- 2(4x + 1) = 11x - 25
- 8x + 2 = 11x - 25
- 11x - 8x = 2 + 25
- 3x = 27
- x = 27/3
- x = 9
DE = 4*9 + 1 = 36 + 1 = 37
