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Ksju [112]
3 years ago
6

The magnitude, M, of an earthquake is defined to be M=log l/s, where l is the intensity of the earthquake (measured by the ampli

tude of the seismograph wave) and S is the intensity of a “standard” earthquake, which is barely detectable. Which equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake?
Mathematics
2 answers:
Stels [109]3 years ago
5 0

Answer:It’s C on edge

Step-by-step explanation:

creativ13 [48]3 years ago
3 0

Answer:

M = Log (10S/S)

Step-by-step explanation:

We are told that the magnitude, M, of an earthquake is defined to be;

M = Log l/S

Where I is intensity and S is standard earthquake.

Now, we want to find the magnitude of an earthquake that is 10 times more intense than a standard earthquake

Since 10 times more intense than standard earthquake, it means that;

I = 10S

So plugging in 10S for I in the original equation for magnitude gives;

M = Log (10S/S)

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USPshnik [31]
If you’re solving for a... subtract the 8 to the other side so...
-4(a+3)- 3(2a-8) = 22.
Distribute the -4 and -3 into the parentheses (two negatives multiplied together is a positive)...
-4a-12-6a+24 = 22.
Add the constants and a’s together.
-10a + 12 = 22
Subtract 12 to the other side.
-10a = 10
Divide both sides by -10.
a = -1
Check and make sure that this answer works with the problem.
-4(-1+3)-3(-2-8)=22
-4(-2)-3(-10)=22.
-8+30=22.
22=22, the answer checks out
8 0
3 years ago
What is 5/8 written as a decimal and a percent?
grandymaker [24]
Im not sure about the percent but as a decimal its <em><u>1.6</u></em>
3 0
4 years ago
Read 2 more answers
Solve for x. 23x=49 x=827 x=23 x = 2 x = 3
3241004551 [841]

Answer:

x = 49/23

Step-by-step explanation:

23x=49

Divide each side by 23

23x/23 = 49/23

x = 49/23

7 0
3 years ago
Estimate the difference to the nearest 10th 0.612-0.185
TEA [102]

Answer:

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Step-by-step explanation:

Round 0.600 - 0.200 = 0.4

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3 years ago
A single​ 6-sided die is rolled twice. the set of 36 equally likely outcomes is​ {(1,1), (1,2),​ (1,3), (1,4), left parenthesis
Nataly [62]

Sum greater than 9 from the Sample Space are:

{(4,6),(5,5),(5,6),(6,4),(6,5),(6,6)}

so, in total 6 out of total 36 combinations have a sum greater than 9

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Probability(sum>9)=\frac{1}{6}

Probability(sum>9)=0.167

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