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Ksju [112]
3 years ago
6

The magnitude, M, of an earthquake is defined to be M=log l/s, where l is the intensity of the earthquake (measured by the ampli

tude of the seismograph wave) and S is the intensity of a “standard” earthquake, which is barely detectable. Which equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake?
Mathematics
2 answers:
Stels [109]3 years ago
5 0

Answer:It’s C on edge

Step-by-step explanation:

creativ13 [48]3 years ago
3 0

Answer:

M = Log (10S/S)

Step-by-step explanation:

We are told that the magnitude, M, of an earthquake is defined to be;

M = Log l/S

Where I is intensity and S is standard earthquake.

Now, we want to find the magnitude of an earthquake that is 10 times more intense than a standard earthquake

Since 10 times more intense than standard earthquake, it means that;

I = 10S

So plugging in 10S for I in the original equation for magnitude gives;

M = Log (10S/S)

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3 years ago
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In a sample of 57 temperature readings taken from the freezer of a restaurant, the mean is 29.6 degrees and the population stand
Natalka [10]

Answer:

(29.14 ; 30.06)

Step-by-step explanation:

Given that'

Sample size (n) = 57

Mean (m) = 29.6

Population standard deviation (σ) = 2.7

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= (1 - 0.8) / 2 = 0.1

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Using the Z probability calculator : Z0. 1 = 1.28

Hence,

29.6 ± 1.28 * (2.7 / √57)

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29.142241664 ; 30.057758336

(29.14 ; 30.06)

8 0
3 years ago
Describe four real-life situations in which you might need to add or subtract decimals.
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Please help will mark brainliest
beks73 [17]

Answer:

m\angle N=57^{\circ}

Step-by-step explanation:

From the isosceles-base theorem, the measure of the angles adjacent to the pair of congruent sides of the triangle are equal. Since the problem declares LM\cong LN, the remaining unknown angles are equal (m\angle N=m\angle M). The sum of the interior angles of a triangle always add up to 180^{\circ}$.

Therefore:

m\angle N\cdot 2+66=180,\\m\angle N\cdot 2=114,\\m\angle N=\fbox{$57^{\circ}$} .

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A regular pentagon has all its five sides equal and all five angles are also equal. Hence, the measure of each interior angle of a regular pentagon is given by the below formula. Measure of each interior angle = [(n – 2) × 180°]/n = 540°/5 = 108°.
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1 year ago
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