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Ksju [112]
3 years ago
6

The magnitude, M, of an earthquake is defined to be M=log l/s, where l is the intensity of the earthquake (measured by the ampli

tude of the seismograph wave) and S is the intensity of a “standard” earthquake, which is barely detectable. Which equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake?
Mathematics
2 answers:
Stels [109]3 years ago
5 0

Answer:It’s C on edge

Step-by-step explanation:

creativ13 [48]3 years ago
3 0

Answer:

M = Log (10S/S)

Step-by-step explanation:

We are told that the magnitude, M, of an earthquake is defined to be;

M = Log l/S

Where I is intensity and S is standard earthquake.

Now, we want to find the magnitude of an earthquake that is 10 times more intense than a standard earthquake

Since 10 times more intense than standard earthquake, it means that;

I = 10S

So plugging in 10S for I in the original equation for magnitude gives;

M = Log (10S/S)

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The"off-peak"weekly average cost of hiring a caravan in wales is £520. In July the average cost increases to £800. Calculate the
mafiozo [28]

Answer: 53.84%

Step-by-step explanation:

Given

The average cost of hiring is £520

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3 years ago
What is m&lt;efh =(5×+1)°,m&lt;hfg =62° and m &lt;efg = (18×+11)°, find each measure.​
Naddik [55]

Answer:

m\angle efg=21\°\\\\m\angle hfg=62\°\\\\m\angle efg=83\°

Step-by-step explanation:

Given:

m\angle efh=5x+1\\m\angle hfg=62\\m\angle efg=18x+11

Now, from the figure shown below,

The sum of angle efh and angle hfg is equal to the angle efg. This is true because of the angle addition postulate which states that when two angles are formed with the same vertex and different sides, then their sum is equal to the total angle made by both the sides at the vertex.

Here, point 'f' is the vertex and the sides are 'ef and 'fg'.

Therefore,

m\angle efh+m\angle hfg=m\angle efg

Plug in their values and solve for 'x'. This gives,

5x+1+62=18x+11\\5x+63=18x+11\\18x-5x=63-11\\13x=52\\x=\frac{52}{13}=4

Therefore, the angle measure of each are:

m\angle efg=5x+1=5(4)+1=20+1=21\°\\\\m\angle hfg=62\°\\\\m\angle efg=18x+11=18(4)+11=72+11=83\°

6 0
4 years ago
Sheldon picked 5 3/10 kg but 1.5 were rotten and thrown out how many kilograms of tomatoes were rotten
Helga [31]

Answer:

<u>1.5 or 1 1/2 kilograms were rotten and thrown out</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Amount of kilograms of tomatoes Sheldon picked = 5 3/10

Amount of kilograms of tomatoes rotten = 1.5

2. How many kilograms of tomatoes were rotten?

<u>1.5 or 1 1/2 kilograms were rotten and thrown out</u>

5 0
3 years ago
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