Answer:
de Broglie wavelength of the bullet is 3.093 x 10⁻³⁵ m
Explanation:
Given;
mass of bullet, m = 28 g = 0.028 kg
velocity of the bullet, v = 765 m/s
de Broglie wavelength of the bullet is given by;
λ = h / mv
where;
λ is de Broglie wavelength of the bullet
h is Planck's constant = 6.626 x 10⁻³⁴ J/s
λ = h / mv
λ = (6.626 x 10⁻³⁴ ) / (0.028 x 765)
λ = 3.093 x 10⁻³⁵ m
Therefore, de Broglie wavelength of the bullet is 3.093 x 10⁻³⁵ m
Answer:
30×6=n
Explanation:
30 students in her class× 6 = number of students in the entire 4th grade.
The magnitude of the electric field at this location is 
<u>Explanation:</u>
Given
Electric field at this location determined by the force and charge.
E=F/Q
Glaciers<span> begin to </span>form<span> when snow remains in the same area year-round, where enough snow accumulates to transform into ice. Each year, new layers of snow bury and compress the previous layers. This compression forces the snow to re-crystallize, forming grains similar in size and shape to grains of sugar.</span>
