1. The problem statement, all variables and given/known data A parallel-plate capacitor of capacitance C with circular plates is charged by a constant current I. The radius a of the plates is much larger than the distance d between them, so fringing effects are negligible. Calculate B(r), the magnitude of the magnetic field inside the capacitor as a function of distance from the axis joining the center points of the circular plates. 2. Relevant equations When a capacitor is charged, the electric field E, and hence the electric flux Φ, between the plates changes. This change in flux induces a magnetic field, according to Ampère's law as extended by Maxwell: ∮B⃗ ⋅dl⃗ =μ0(I+ϵ0dΦdt). You will calculate this magnetic field in the space between capacitor plates, where the electric flux changes but the conduction current I is zero.
Answer:
D . Sound energy
Explanation:
When the strings of a violin vibrate it produces sound which is sound energy. Due to the vibration of the strings the air present near the strings also vibrate in resonance with the strings. This compreesion and decompression's produced in the air is nothing but the sound. So the form of energy given off by the vibrating strings of the violin is Sound energy.
Answer:
her displacement <em>s=337.5m</em>
Explanation:
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Answer: Mineral and non- mineral components circulate in the environment in different forms whether it is in the form of solid, liquid, or gas.
Explanation:
Plants take up the minerals like calcium, potassium, nitrogen, sulphur, and others from the soil and utilize them for their survival and growth. These minerals are stored in the flowers, leaves, roots, and other plant parts and these plant parts are consumed by humans and animals. So, inorganic minerals from the soil are converted into organic forms by the plants again the minerals are decomposed into inorganic forms after the death of organisms and again mineral is converted into inorganic form in the soil and these minerals can become the component of the rocks after the sedimentation of the soil.
The electric field strength will be 0.6252 V/m. It is the strength at which the field is created by charges.
<h3>What is electric file strength?</h3>
The electric field strength is defined as the ratio of electric force and charge.
The electric field strength is found as;

Hence, the electric field strength will be 0.6252 V/m.
To learn more about the electric field strength, refer to the link;
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