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NeTakaya
3 years ago
12

Why are satellites placed into orbit at least 150 km above Earth’s surface?

Physics
2 answers:
dybincka [34]3 years ago
8 0
Because its just enough to where its not out f the gravitational pull and not close enough to be pulled back to earth. Hope it helps<span />
Anna007 [38]3 years ago
7 0

It's TO AVOID AIR RESISTANCE on E2020. Hope I helped :)

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Which of the following observations indicates that an object is falling at terminal velocity?
vitfil [10]

Answer:  D

Explanation:

When an object falls gravity is pulling down on it and is picking up speed, but as it gains speed air resistance becomes a faster. Air resistance increases with speed. And that force keeps it from accelerating eventually the object will pick up speed such that the force due to air resistance will keep it from getting any more speed at that point force due to air resistance is equal to its weight (mg) and the net force is equal to zero so it won’t accelerate any more at that point it is said to be moving in terminal velocity.

When an object has reached terminal velocity, it will have a constant velocity

5 0
4 years ago
A ball dropped from a window strikes the ground 2.76 seconds later. How high is the window above the ground
sweet [91]

Answer:

37.33m

Explanation:

Using the equation of motion

S = ut + 1/2gt^2

Time t = 2.76secs

g = 9.8m/s^2

S = 0 + 1/2(9.8)(2.76)^2

S = 4.9*7.6176

S = 37.33

Hence the window is 37.33m above the ground

7 0
3 years ago
An object on earth weighs 120 N. What is it’s mass ?
inna [77]
Weight = (mass) x (gravity)

120 N = (mass) x (9.8 m/s²)

Mass = (120 N) / (9.8 m/s²)

Mass = 12.24 kg  (B)
7 0
3 years ago
Read 2 more answers
A slender rod is 80.0 cm long and has mass 0.390 kg . A small 0.0200-kg sphere is welded to one end of the rod, and a small 0.05
Keith_Richards [23]

Answer

given,

length of slender rod =80 cm = 0.8 m

mass of rod = 0.39 Kg

mass of small sphere = 0.0200 kg

mass of another sphere weld = 0.0500 Kg

calculating the moment of inertia of the system

I = \dfrac{ML^2}{12}+\dfrac{m_1L^2}{4}+\dfrac{mL^2}{4}

I = \dfrac{0.39\times 0.8^2}{12}+\dfrac{0.02\times 0.8^2}{4}+\dfrac{0.05\times 0.8^2}{4}

I =0.032\ kg.m^2

using conservation of energy

\dfrac{1}{2}I\omega^2 = (m_1-m_2)g\dfrac{L}{2}

\omega=\sqrt{\dfrac{(m_1-m_2)gL}{I}}

\omega=\sqrt{\dfrac{(0.05-0.02)\times 9.8 \times 0.8}{0.032}}

\omega=2.71 \rad/s

we know,

v = r ω

v = \dfrac{L}{2} \times 2.71

v = \dfrac{0.8}{2} \times 2.71

v = 1.084 m/s

3 0
4 years ago
What temperature is required to transfer waste heat to the environment for a heat engine to be 100 percent efficient?
OLEGan [10]
This can be seen as a trick question because heat engines can typically never be 100 percent efficient. This is due to the presence of inefficiencies such as friction and heat loss to the environment. Even the best heat engines can only go up to around 50% efficiency.
6 0
3 years ago
Read 2 more answers
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