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wolverine [178]

3 years ago

12

The two numbers between the square root of two

2 answers:

KatRina [158]3 years ago

8 0

Answer:

1 and 1.5

Step-by-step explanation:

but im not sure

Arlecino [84]3 years ago

8 0

Answer:

1 and 1.5

Step-by-step explanation:

the square root of 2 is 1.414... so the two numbers it would be between is q and 1.5

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3x + 15 - 2× + 10 + × + 5

likoan [24]

Answer is 58 duh dude

6 0

3 years ago

Pavlova-9 [17]

3 3/12 is one of them

5 0

3 years ago

Find the area of the circle and the sector.

Georgia [21]

Area of a circle is PI x r^2:

Area of circle = 3.14 x 13^2 = 530.66 square meters.

To find the area of the sector multiply the area of the circle by the fraction of the sector

Area of sector = 530.66 x 150/360 = 221.108 square meters ( Round the answer as needed).

6 0

3 years ago

In a walk fir charity,you. Walk at a rate of 100 meters per minute.how long does it take you to walk 2 kilometers

Ivahew [28]

20 minutes

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100/1= 2000/X
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7 0

3 years ago

Help please and thanks! I'll award brainliest if you show your work as well :)

iren2701 [21]

Answer:

6 inches

Step-by-step explanation:

Formula for surface area of a cylinder:

$SA=2\pi r^{2} +2\pi rh$

Plug in values and solve for the radius:

$180\pi =2\pi r^{2} +2\pi r(9)\\$

Divide both sides by $2\pi$

$90=r^{2} +r(9)$

Subtract 90 from both sides

$0=r^{2} +9r-90$

Use the quadratic equation to find the roots

$x=(-b$ ± $\sqrt{b^2-4ac})*\frac{1}{2a}$ (sorry for formatting, Brainly doesn't

allow equations with ± in them)

$x=\frac{-9+\sqrt{9^2-4*1*90} }{2(1)}$ and $x=\frac{-9-\sqrt{9^2-4*1*90} }{2(1)}$

$x=\frac{(-9+\sqrt{81+360})}{2}$ and $x=\frac{(-9-\sqrt{81+360})}{2}$

$x=\frac{(-9+\sqrt{441})}{2}$ and $x=\frac{(-9-\sqrt{441})}{2}$

$x=\frac{(-9+21)}{2}$ and $x=\frac{(-9-21)}{2}$

$x=\frac{12}{2}$ and $x=\frac{-30}{2}$

$x=6$ and $x=-15$

We can't have a negative radius, so that leaves us with r=6 in.

8 0

2 years ago