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wolverine [178]
3 years ago
12

The two numbers between the square root of two

Mathematics
2 answers:
KatRina [158]3 years ago
8 0

Answer:

1 and 1.5

Step-by-step explanation:

but im not sure

Arlecino [84]3 years ago
8 0

Answer:

1 and 1.5

Step-by-step explanation:

the square root of 2 is 1.414... so the two numbers it would be between is q and 1.5

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(12 divided by 3) 2 – (18 divided by 3 2)) < (4 divided by 2)
gladu [14]

Answer:

(12 \div 3)(2 - (18 \div 32) \\  = 4(2 -  \frac{19}{16} ) \\  = 4( \frac{23}{16} ) \\  =  \frac{23}{4}  \\ since \: (4 \div 2) = 2 \\  \frac{23}{4} is \: not \:  < 2 \: but \: its \:  > 2

4 0
3 years ago
Consider the gender and class make-up of students at a large university by gender and status as given in the table.
azamat

Answer:

0.589

Step-by-step explanation:

THis is a conditional probability question. Let's look at the formula first:

P (A | B) = P(A∩B)/P(B)

" | " means "given that".

So, it means, the <u><em>"Probabilty A given that B is equal to Probability A intersection B divided by probability of B."</em></u>

<u><em /></u>

So we want to know P (Female | Undergraduate ). This in formula is:

P (Female | Undergraduate) = P (Female ∩ Undergraduate)/P(Undergraduate)

Now,

P (Female ∩ Undergraduate) means what is common in both female and undergraduate? There are 43% female that are undergrads. Hence,

P (Female ∩ Undergraduate) = 0.43

Also,

P (Undergraduate) is how many undergrads are there? There are 73% undergrads, so that is P (undergraduate) = 0.73

<em>plugging into the formula we get:</em>

P (Female | Undergraduate) = P (Female ∩ Undergraduate)/P(Undergraduate)

=0.43/0.73 = 0.589

this is the answer.

4 0
3 years ago
Can someone help me with this?
Arisa [49]

Answer:

look at the picture

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Find two positive integers such that the sum of the first number and four times the second number is 1000, and the product of th
vladimir2022 [97]

Answer:

The two numbers are:

x = 500

y = 125

Step-by-step explanation:

We want to find two numbers x and y, such that:

x + 4*y = 1000

f(x, y) = x*y is maximum.

From the first equation, we can isolate one of the variables to get

x = 1000 - 4y

now we can replace it in f(x, y):

x*y = (1000 - 4*y)*y  = 1000*y - 4*y^2

So now we want to maximize the function:

f(y) =- 4*y^2 + 1000*y

where y must be an integer.

Notice that this is a quadratic equation with a negative leading coefficient (so the arms of the graph will open downwards), thus, the maximum will be at the vertex.

Remember that for a general quadratic equation:

y = a*x^2 + bx + c

the x-value of the vertex is:

x = -b/(2*a)

so, in the case of:

f(y) =- 4*y^2 + 1000*y

the y-value of the vertex will be:

y = -1000/(2*-4) = 1000/8 = 125

So we found the value of y.

now we can use the equation:

x = 1000 - 4*y

x = 1000 - 4*125 = 1000 - 500 = 500

x = 500

Then the two numbers are:

x =500

y = 125

6 0
2 years ago
(3 3/4)÷(−2 1/2)
Ierofanga [76]

Answer:

-1 1/2

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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