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chubhunter [2.5K]
3 years ago
6

Find the volume of this sphere. Use 3 for TT. V V ~ [?]cm3 V = nr3 r=6cm

Mathematics
1 answer:
Katen [24]3 years ago
6 0

Answer:

V = 864cm^3

Step-by-step explanation:

Given

r = 6

\pi = 3

Required

The volume of the sphere

This is calculated as:

V = \frac{4}{3} \pi r^3

So, we have:

V = \frac{4}{3} *3 *6^3

V = \frac{4}{3} *3 *216

This gives:

V = 4 *216

V = 864

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<h3>Answer:  18</h3>

Work Shown:

area = length*width

length = area/width

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7 0
2 years ago
A line and the point (3,4) are graphed in the coordinate plane. what is the equation of the line that passes through the point (
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Answer:

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Step-by-step explanation:

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2 years ago
Y = 7/8u + 9, solve for u
vivado [14]

Answer:

u=\frac{8y-72}{7}

Step-by-step explanation:

Flip the equation.

\frac{7}{8}u+9=y

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\frac{7}{8}u+9(-9)=y(-9)

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hope this helps

3 0
3 years ago
A polynominal function that describes an enclosure is v(x)=1500x_x2 where x is the length of the fence in feet what is the maxim
Maksim231197 [3]

Answer:

The answer is below

Step-by-step explanation:

A polynominal function that describes an enclosure is v(x)=1500x-x2 where x is the length of the fence in feet what is the maximum area of the enclosure

Solution:

The maximum area of the enclosure is gotten when the differential with respect to x of the enclosure function is equal to zero. That is:

V'(x) = 0

V(x) = x(1500 - x) = length * breadth.

This means the enclosure has a length of x and a width of 1500 - x

Given that:

v(x)=1500x-x². Hence:

V'(x) = 1500 -2x

V'(x) = 0

1500 -2x = 0

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x = 1500 / 2

x = 750 feet

The maximum area = 1500(750) - 750² = 562500

The maximum area = 562500 feet²

3 0
3 years ago
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katrin [286]

Answer:$8

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3 0
3 years ago
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