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3 years ago

Find the volume of this sphere. Use 3 for TT. V V ~ [?]cm3 V = nr3 r=6cm

Mathematics

1 answer:

Katen [24]3 years ago

6 0

Answer:

$V = 864cm^3$

Step-by-step explanation:

Given

$r = 6$

$\pi = 3$

Required

The volume of the sphere

This is calculated as:

$V = \frac{4}{3} \pi r^3$

So, we have:

$V = \frac{4}{3} *3 *6^3$

$V = \frac{4}{3} *3 *216$

This gives:

$V = 4 *216$

$V = 864$

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A graphing calculator is recommended. A function is given. g(x) = x4 − 5x3 − 14x2 (a) Find all the local maximum and minimum val

Taya2010 [7]

Answer:

The local maximum and minimum values are:

Local maximum

$g(0) = 0$

Local minima

$g(5.118) = -350.90$

$g(-1.368) = -9.90$

Step-by-step explanation:

Let be $g(x) = x^{4}-5\cdot x^{3}-14\cdot x^{2}$ . The determination of maxima and minima is done by using the First and Second Derivatives of the Function (First and Second Derivative Tests). First, the function can be rewritten algebraically as follows:

$g(x) = x^{2}\cdot (x^{2}-5\cdot x -14)$

Then, first and second derivatives of the function are, respectively:

First derivative

$g'(x) = 2\cdot x \cdot (x^{2}-5\cdot x -14) + x^{2}\cdot (2\cdot x -5)$

$g'(x) = 2\cdot x^{3}-10\cdot x^{2}-28\cdot x +2\cdot x^{3}-5\cdot x^{2}$

$g'(x) = 4\cdot x^{3}-15\cdot x^{2}-28\cdot x$

$g'(x) = x\cdot (4\cdot x^{2}-15\cdot x -28)$

Second derivative

$g''(x) = 12\cdot x^{2}-30\cdot x -28$

Now, let equalize the first derivative to solve and solve the resulting equation:

$x\cdot (4\cdot x^{2}-15\cdot x -28) = 0$

The second-order polynomial is now transform into a product of binomials with the help of factorization methods or by General Quadratic Formula. That is:

$x\cdot (x-5.118)\cdot (x+1.368) = 0$

The critical points are 0, 5.118 and -1.368.

Each critical point is evaluated at the second derivative expression:

x = 0

$g''(0) = 12\cdot (0)^{2}-30\cdot (0) -28$

$g''(0) = -28$

This value leads to a local maximum.

x = 5.118

$g''(5.118) = 12\cdot (5.118)^{2}-30\cdot (5.118) -28$

$g''(5.118) = 132.787$

This value leads to a local minimum.

x = -1.368

$g''(-1.368) = 12\cdot (-1.368)^{2}-30\cdot (-1.368) -28$

$g''(-1.368) = 35.497$

This value leads to a local minimum.

Therefore, the local maximum and minimum values are:

Local maximum

$g(0) = (0)^{4}-5\cdot (0)^{3}-14\cdot (0)^{2}$

$g(0) = 0$

Local minima

$g(5.118) = (5.118)^{4}-5\cdot (5.118)^{3}-14\cdot (5.118)^{2}$

$g(5.118) = -350.90$

$g(-1.368) = (-1.368)^{4}-5\cdot (-1.368)^{3}-14\cdot (-1.368)^{2}$

$g(-1.368) = -9.90$

7 0

3 years ago

Consider the right triangle. A right triangles with side lengths 28 meters and 45 meters. The hypotenuse is unknown. What is the

omeli [17]

Answer:

The answer is 53 or Square Root (sqrt) of 2809

Step-by-step explanation:

a^2+b^2=c^2

28^2+45^2=c^2

784+2025=c^2

c^2=sqrt 2809

c = 53

8 0

3 years ago

Read 2 more answers

Which expression is equivalent to mc014-1?

ryzh [129]

1/5(100x - 105y + 70) = 20x -21y + 14

8 0

3 years ago

Find the volume of this

11111nata11111 [884]

Answer:

37.8 yd^3

Step-by-step explanation:

base area = (4.5 x 2.8)/2 = 6.3 yd^2

Volume = 6.3 x 6 = 37.8 yd^3

4 0

2 years ago

Yolanda’s club require that 60% of the members be present for any vote. If at least 30 members must be present to have a vote ho

balandron [24]

We can rewrite this problem as:
What is 60% of 35?
"Percent" or "%" means "out of 100" or "per 100", Therefore 60% can be written as
60
100
.
When dealing with percents the word "of" means "times" or "to multiply".
Finally, lets call the number of members we are looking for "m".
Putting this altogether we can write this equation and solve for
m
while keeping the equation balanced:
m
=
60
100
×
35
m
=
2100
100
m
=
21
21
members must be present to have a vote.

8 0

3 years ago

Read 2 more answers