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3 years ago

Find the volume of this sphere. Use 3 for TT. V V ~ [?]cm3 V = nr3 r=6cm

Mathematics

1 answer:

Katen [24]3 years ago

6 0

Answer:

$V = 864cm^3$

Step-by-step explanation:

Given

$r = 6$

$\pi = 3$

Required

The volume of the sphere

This is calculated as:

$V = \frac{4}{3} \pi r^3$

So, we have:

$V = \frac{4}{3} *3 *6^3$

$V = \frac{4}{3} *3 *216$

This gives:

$V = 4 *216$

$V = 864$

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I need help with this! Quick ASAP?

sp2606 [1]

Answer:

a) F

b) B, E, D

Step-by-step explanation:

a) The segment with the greatest gradient has the largest change in y-values per unit change in x-values

From the given option, the rate of change of the y to the x-values of B = the gradient = (4 units)/(2 units) = 2

The gradient of F = (-3units)/(1 unit) = -3

The gradient of A = 4/4 = 1

The gradient of C = -2/5

The gradient of D = 2/6 = 1/3

The gradient of E = 3/4

The segment with the greatest gradient is F

b) The steepest segment has the higher gradient

From their calculated we have;

The gradient of segment B = 2 therefore, B is steeper than E that has a gradient of 3/4, and E is steeper than D, as the gradient of D = 1/3

Therefore, we have;

B, E, D.

6 0

3 years ago

The surface area S , of a right rectangular prism with length l , width w ,and height h can be found using the formula below

Yakvenalex [24]

First, replace all variables with the given values.
12(9) + 9(2) + 2(12)
This should then equal 150, then the formula says to multiply this answer by 2. Doing so, should give a final answer of 300.

3 0

3 years ago

Now there is a square city of unknown size with a gate at the center of each side. There is a tree 20 b from the north gate. Tha

Brums [2.3K]

Answer:

The length of each side of the city is 250b

Step-by-step explanation:

Given

$a = 20$ --- tree distance from north gate

$b =14$ --- movement from south gate

$c = 1775$ --- movement in west direction from (b)

See attachment for illustration

Required

Find x

To do this, we have:

$\triangle ADE \sim \triangle ACB$ --- similar triangles

So, we have the following equivalent ratios

$AE:DE = AB:CB$

Where:

$AE = 20\\ DE = x/2 \\ AB = 20 + x + 14 \\ CB = 1775$

Substitute these in the above equation

$20:x/2 = 20 + x + 14: 1775$

$20:x/2 = x + 34: 1775$

Express as fraction

$\frac{20}{x/2} = \frac{x + 34}{1775}$

$\frac{40}{x} = \frac{x + 34}{1775}$

Cross multiply

$x *(x + 34) = 1775 * 40$

Open bracket

$x^2 + 34x = 71000$

Rewrite as:

$x^2 + 34x - 71000 = 0$

Expand

$x^2 + 284x -250x - 71000 = 0$

Factorize

$x(x + 284) -250(x + 284)= 0$

Factor out x + 284

$(x - 250)(x + 284)= 0$

Split

$x - 250 = 0 \ or\ x + 284= 0$

Solve for x

$x = 250 \ or\ x =- 284$

x can't be negative;

So:

$x = 250$

6 0

3 years ago

Solve for x x + a = b

ohaa [14]

X+a=b
you want to isolate x so subtract a from both sides

x=b-a

6 0

3 years ago

Read 2 more answers

Answer the question correctly.

sleet_krkn [62]

Answer:

the answer is 10 to the tenth power or 10000000000

Step-by-step explanation:

5 0

2 years ago