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Lubov Fominskaja [6]
3 years ago
7

1/4 and 1/2 common denominators​

Mathematics
2 answers:
Paha777 [63]3 years ago
5 0

Answer:

4

Step-by-step explanation:

Lunna [17]3 years ago
5 0

Answer:

The common denominator of 1/4 and 1/2 is 4.

1/2 = 2/4

You might be interested in
Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li
krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years

First, let us calculate the decay constant (k)

75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036

Next, let us calculate the half-life as follows:

\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2}  \approx 669\ years

Therefore the half-life is between 600 and 700 years

5 0
3 years ago
Y=6x-11 -2x-3y=-7 solve each system of equation by substitution
Anit [1.1K]

Answer:

(2, 1 )

Step-by-step explanation:

Given the 2 equations

y = 6x - 11 → (1)

- 2x - 3y = - 7 → (2)

Substitute y = 6x - 11 into (2)

- 2x - 3(6x - 11) = - 7 ← distribute and simplify left side

- 2x - 18x + 33 = - 7

- 20x + 33 = - 7 ( subtract 33 from both sides )

- 20x = - 40 ( divide both sides by - 20 )

x = 2

Substitute x = 2 into (1) for corresponding value of y

y = 6(2) - 11 = 12 - 11 = 1

Solution is (2, 1 )

5 0
3 years ago
Evaluate -3x² + 4x-2 for x = 2.<br> A. -2<br> B. -1<br> C. -6<br> D. 18
kobusy [5.1K]

Answer:

C. -6

Step-by-step explanation:

-3(2)²+4(2)-2

-3(4) + 8 - 2

-12+8-2

-14+8

-6

5 0
2 years ago
The water cycle describes how water __ from the ocean ,plants ,animalas or waste
notsponge [240]

Answer:

evaporates

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
please help!! Drag each pair of equations to show whether the system has no solution, one solution, or infinitely many solutions
Vanyuwa [196]

For the given system of equations, considering different systems are split by ;, we have that:

  • No solutions: 3y = x + 2, 9y = 3x + 7; y = 2x + 3, y = 2x + 5
  • One solution: 2y = 3x, -5y = -10x,; x = 6, y = 9.
  • Infinitely many solutions: y = 5x + 2, 3y = 15x + 6.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

It's equations can be written in the format:

Ax = b

Using the above format, we have that:

  • If A is different from zero, the system has one solution.
  • If A is zero and B is different of zero, the system has no solutions.
  • If both are zero, the system has infinite solutions.

At the first system, multiplying the first equation by -3 and adding with the second, we end up with:

0y = 0x + 2

0 = -2

Which is a false statement, hence it has no solutions.

At the second system, the equations are multiples, hence it has infinite solutions.

At the third system, the coefficients are not zero and are not multiples, and it has one solution.

In the fourth system, the one solution is already given.

At the fifth system, we have that:

2x + 3 = 2x + 5

0x = 2

Hence no solutions.

To learn more about system of equations, you can take a look at brainly.com/question/24342899

5 0
2 years ago
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