C. Find the sum of the two horizontal in the summer for two vertical vectors.
Answer:
The area of the pyramid’s base is 36 in².
The pyramid has 4 lateral faces.
The surface area of each lateral face is 27 in².
Step-by-step explanation:
"<u>Lateral</u>" means side, so the lateral faces are <u>triangles</u>.
The <u>base</u> is the bottom, which is a <u>square</u>.
To calculate the <u>area of the base</u>, use the formula for area of a square.



To calculate the <u>area of a lateral face</u>, find the area of a triangle.




In a pyramid, the number of lateral faces is the same as the number of sides in the base. <u>The square base as 4 sides, so there are 4 lateral faces</u>.
5 and 96/100 or if you need to simplify 5 and 24/25
Answer:
WAKA WAKA AFRICAAAA AFRIKA BAM BAM MAMAMAMAMAMAMAMAMAM.A.
So did I get them 5 bucks?
Answer: A. Mean of sampling means 
Standard deviation of sampling means =
B. The probability that your sample has mean less than 165 is 0.1492 .
Given : The distribution of blood cholesterol level in the
population of young men aged 20 to 34 years is close to normal with
mean
Mg/dl and standard deviation
mg/dl.
Sample size : n= 150
Let
sample mean values.
A. The mean and the standard deviation of the distribution of the sampling means would be :
Mean of sampling means =
Standard deviation of sampling means = 

The probability that your sample has mean less than 165 would be

Hence , the probability that your sample has mean less than 165 is 0.1492 .