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PIT_PIT [208]
3 years ago
6

True or false:

Mathematics
1 answer:
MArishka [77]3 years ago
6 0

Answer:A. True, cause they have four sides

B. True cause if you turn them a little they look like a square

Step-by-step explanation:

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What is this problem
sergeinik [125]

Answer:

m=A-\frac{2n}{Z}

Step-by-step explanation:

Multiply by 2:

2n = Z(A - m)

Divide by Z:

\frac{2n}{Z} =A-m

Subtract A:

-m=\frac{2n}{Z}-A

Multiply by -1:

m=A-\frac{2n}{Z}

3 0
3 years ago
How much grain can this container hold ? express your answer in terms of <img src="https://tex.z-dn.net/?f=%5Cpi" id="TexFormula
IRINA_888 [86]

Answer:

44 because if you multiple 4 x 11 it would give you 44

3 0
2 years ago
Help mathh PLEAEE HELP​
Bess [88]

this is as far as i could get. sorry

8 0
3 years ago
Problem:
Molodets [167]

Answer:

a)

We know that:

a, b > 0

a < b

With this, we want to prove that a^2 < b^2

Well, we start with:

a < b

If we multiply both sides by a, we get:

a*a < b*a

a^2 < b*a

now let's go back to the initial inequality.

a < b

if we now multiply both sides by b, we get:

a*b < b*b

a*b < b^2

Then we have the two inequalities:

a^2 < b*a

a*b < b^2

a*b = b*a

Then we can rewrite this as:

a^2 < b*a < b^2

This means that:

a^2 < b^2

b) Now we know that a.b > 0, and a^2 < b^2

With this, we want to prove that a < b

So let's start with:

a^2 < b^2

only with this, we can know that a*b will be between these two numbers.

Then:

a^2 < a*b < b^2

Now just divide all the sides by a or b.

if we divide all of them by a, we get:

a^2/a < a*b/a < b^2/a

a < b < b^2/a

In the first part, we have a < b, this is what we wanted to get.

Another way can be:

a^2 < b^2

divide both sides by a^2

1 < b^2/a^2

Let's apply the square root in both sides:

√1 < √( b^2/a^2)

1 < b/a

Now we multiply both sides by a:

a < b

7 0
3 years ago
Will buys a case of vitamins for $56. Each case contains 7 bottles. How much does each bottle cost?​
liberstina [14]

Answer:

$8.00 a bottle.

Step-by-step explanation:

5 0
3 years ago
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