5. |4| = ___ 6. |-2 1/2| = _ 7. |-8.673| = _ 8. |-1,834| = ___

Mathematics

1 answer:

MatroZZZ [7]2 years ago

6 0

Answer:

The absolute value is the distance between a number and zero. The distance between −7 - 7 and 0 0 is 7 7 . 7 7. |−7| | - 7 | ...

Step-by-step explanation:

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Marat540 [252]

Answer:

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8 0

2 years ago

Calculate the second moment of area of a 4-in-diameter shaft about the x-x and yy axes, as shown.

Keith_Richards [23]

Second moment of area about an axis along any diameter in the plane of the cross section (i.e. x-x, y-y) is each equal to (1/4)pi r^4.
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int int y^2 dA
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2 years ago

Please help meeeee!!!!!!! complete the equation below. 5x+5x=10x____

saul85 [17]

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5 0

3 years ago

The rate of change of the number of mountain lions N(t) in a population is directly proportional to 725 - N(t), where t is the t

wolverine [178]

Answer:

a) The implied differential equation is $\frac{dN}{725 - N} = kdt$

b) The general equation is $N = 725 - C e^{-kt}$

c) The particular equation is $N = 725 - 325 e^{-0.49t}$

d) The population when t = 5, N(5) = 697 = 700( to the nearest 50)

Step-by-step explanation:

The rate of change of N(t) can be written as dN/dt

According to the question, $\frac{dN}{dt} \alpha (725 - N(t))$

$\frac{dN}{dt} = k (725 - N)\\\frac{dN}{725 - N} = kdt$

Integrating both sides of the equation

$\int {\frac{1 }{725 - N}} \, dN = \int {k} \, dt\\- ln (725 - N) = kt + C\\ ln (725 - N) = -(kt + C)\\725 - N = e^{-(kt + C)} \\725 - N = e^{-kt} * e^{-C} \\725 - N = C e^{-kt}\\N = 725 - C e^{-kt}$